News1 min ago
Light Intensity
1 Answers
If light intensity is inversely proportional to resistance, then light intensity is proportional to current due to V=IR. So will a graph of light intensity v wavelength look the same as current v wavelength.
And can this current just be measured by having and LDR and an ammeter in series with constant voltage? thanks
And can this current just be measured by having and LDR and an ammeter in series with constant voltage? thanks
Answers
Only 1 answer
Best Answer
No best answer has yet been selected by JoeParkinson. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.
A graph of Resistance versus Light Intensity will be a curve of negative gradient. Light Intensity and Wavelength are independent of each other. An LDR, such as an ORP 12, will have a resistance in the dark of about 2 million Ohms and a resistance in bright sunlight of about 80 Ohms. Consequently, your ammeter will have to have a very large range. eg. if your constant voltage is 12 Volts, then the current will range from 0.15A (light) to 6 microamps (dark)
Only 1 answer
