ChatterBank2 mins ago
How do you sole this puzzle?
6 Answers
Each letter of the Alphabet has been given a different number value between 1 and 26.
A (?);B(C+N);C(E/K);D(?);
E(R-K);F(Less thanX);G(R-U);H=3;
I(Z-H);J(more thanT);K(?);L=10;
M(T-C);N=4;O(less than Z);P(D/K);Q(R-B)
R(D-K);S=6;T(GxK);U(Less than C);
V(less thanD);W(less than R);X(R/N);
Y(L+M);Z(J-C)
A (?);B(C+N);C(E/K);D(?);
E(R-K);F(Less thanX);G(R-U);H=3;
I(Z-H);J(more thanT);K(?);L=10;
M(T-C);N=4;O(less than Z);P(D/K);Q(R-B)
R(D-K);S=6;T(GxK);U(Less than C);
V(less thanD);W(less than R);X(R/N);
Y(L+M);Z(J-C)
Answers
Okay. So B=C+N and you know N=4 so B= c+4.
It's just a long winded process of substitition , solving equations and maybe some trial and error
It's just a long winded process of substitition , solving equations and maybe some trial and error
12:05 Fri 13th Jan 2012
You can find some others or narrow values down quite quickly too.
For example since X= R/4 then there are limited possible combinations for X and R (1 and 4, 2 and 8, 3 and 12, 4 and 16, 5 and 20 and 6 and 24). You can rule most of these out though because 3, 4 and 6 have already been accounted for (as H, N and S)- so that leaves only 2 and 8 or 5 and 20 as possible combinations for X and R
For example since X= R/4 then there are limited possible combinations for X and R (1 and 4, 2 and 8, 3 and 12, 4 and 16, 5 and 20 and 6 and 24). You can rule most of these out though because 3, 4 and 6 have already been accounted for (as H, N and S)- so that leaves only 2 and 8 or 5 and 20 as possible combinations for X and R
Related Questions
Sorry, we can't find any related questions. Try using the search bar at the top of the page to search for some keywords, or choose a topic and submit your own question.