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Mass Of Co2 Formed In Hcl+Na2Co3 Reaction?

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carlcarlcarl | 13:52 Tue 15th Jan 2019 | Science
5 Answers
2HCl + Na2CO3 => 2NaCl + CO2 +H2O

HCl and Na2CO3 both have volume of 20cm3, concentration 2M.
The question is what mass of CO2 in g is produced.

I calculated that the number of moles for the limiting Na2CO3 is 0.0016, then m=n x Mr makes the mass of CO2 0.0704 g. However, the real answer I was given by the exam board is 0.88. I don't know what I haven't tried and I ran out of ideas. Can anyone tell me what my mistake is?
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Can you briefly set out how you arrived at your answer please, carl. I can't remember all the atomic weights ( in know C and O but not sodium). i'll get some pen and paper out later to check your calculation.
I have done it and get two answers (can't decide which is right until I check it again)- one is the 0.88 given by the setter and the other is double that , i.e. 1.76.
I suspect the 0.88 is right.
I don't get yours at all. I don't see where your 0.0016 comes from (I get 0.04 or 0.02 moles). Even if I were to use your figure of 0.0016 moles I'd get 0.0768g rather than 0.0704g.

It would help if you could set out your working so I can look more closely.
Oops sorry- should have used pen and paper: I would get your 0.0704 if I used your calculated moles figure. But I still don't see where your moles figure came from- I get a much higher figure which results in a much higher weight for CO2
Just did it again with pen and paper and I still get the same answer for the weight of CO₂ . Yours looks wrong to me. Do you want to set out how you got 0.0704?
Did you resolve this, carlcarlcarl? You can reply to your own questions to add information, comments, etc

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