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Mass Of Co2 Formed In Hcl+Na2Co3 Reaction?
5 Answers
2HCl + Na2CO3 => 2NaCl + CO2 +H2O
HCl and Na2CO3 both have volume of 20cm3, concentration 2M.
The question is what mass of CO2 in g is produced.
I calculated that the number of moles for the limiting Na2CO3 is 0.0016, then m=n x Mr makes the mass of CO2 0.0704 g. However, the real answer I was given by the exam board is 0.88. I don't know what I haven't tried and I ran out of ideas. Can anyone tell me what my mistake is?
HCl and Na2CO3 both have volume of 20cm3, concentration 2M.
The question is what mass of CO2 in g is produced.
I calculated that the number of moles for the limiting Na2CO3 is 0.0016, then m=n x Mr makes the mass of CO2 0.0704 g. However, the real answer I was given by the exam board is 0.88. I don't know what I haven't tried and I ran out of ideas. Can anyone tell me what my mistake is?
Answers
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No best answer has yet been selected by carlcarlcarl. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.I have done it and get two answers (can't decide which is right until I check it again)- one is the 0.88 given by the setter and the other is double that , i.e. 1.76.
I suspect the 0.88 is right.
I don't get yours at all. I don't see where your 0.0016 comes from (I get 0.04 or 0.02 moles). Even if I were to use your figure of 0.0016 moles I'd get 0.0768g rather than 0.0704g.
It would help if you could set out your working so I can look more closely.
I suspect the 0.88 is right.
I don't get yours at all. I don't see where your 0.0016 comes from (I get 0.04 or 0.02 moles). Even if I were to use your figure of 0.0016 moles I'd get 0.0768g rather than 0.0704g.
It would help if you could set out your working so I can look more closely.
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