Crosswords1 min ago
More Snooker Loopies
Following on from an earlier question:
http://www.theanswerb.../Question1074615.html
Anyone know the minimum number of points that can be scored in order to win a frame of snooker? (Warning, like the riddle which overtook the earlier question, it involves a bit of highly theoretical play!).
http://www.theanswerb.../Question1074615.html
Anyone know the minimum number of points that can be scored in order to win a frame of snooker? (Warning, like the riddle which overtook the earlier question, it involves a bit of highly theoretical play!).
Answers
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For more on marking an answer as the "Best Answer", please visit our FAQ.I'll go 17
I come to the table trailing 4-14, my opponent having potted all 15 reds and then gone in-off, but subsequently (and having retired with a large sum of cash for the greatest fluke in snooker history) after subsequently having cleared to the pink
And I pot the remaining balls to win 17-14.
However, no doubt there is a lower answer...
I come to the table trailing 4-14, my opponent having potted all 15 reds and then gone in-off, but subsequently (and having retired with a large sum of cash for the greatest fluke in snooker history) after subsequently having cleared to the pink
And I pot the remaining balls to win 17-14.
However, no doubt there is a lower answer...
Times up! (and I’m off out for a Ruby).
No, although I hadn’t discounted retiring in my question, ll_billym, it wasn’t the answer I was looking for.
The answer is 16. Player One comes to the table (with no score on the scoreboard for either player). He pots all fifteen reds off one stroke but goes in off (I had warned you!). So, no points for him, four to his opponent and all the reds are gone. The remaining 27 for the colours can then be split however you like so that one player reaches 16, and the other 15.
No, although I hadn’t discounted retiring in my question, ll_billym, it wasn’t the answer I was looking for.
The answer is 16. Player One comes to the table (with no score on the scoreboard for either player). He pots all fifteen reds off one stroke but goes in off (I had warned you!). So, no points for him, four to his opponent and all the reds are gone. The remaining 27 for the colours can then be split however you like so that one player reaches 16, and the other 15.