Donate SIGN UP

Microwave Oven

Avatar Image
deepak.yadav | 23:40 Mon 17th Mar 2008 | Science
2 Answers
In a certain microwave oven on high power, the time it takes a randomly chosen kernel of popcorn to pop is normally distributed with a mean of 140 seconds and a standard deviation of 25 seconds. What percentage of kernels will fail to pop if the popcorn is cooked for
(a) 2 minutes? (b) 3 minutes? (c) if you wanted 95% of the kernels to pop, what time would you allow? (d) If you wanted 99% to pop?
Gravatar

Answers

1 to 2 of 2rss feed

Best Answer

No best answer has yet been selected by deepak.yadav. Once a best answer has been selected, it will be shown here.

For more on marking an answer as the "Best Answer", please visit our FAQ.
Just use the formula for normal distribution or use the normal distribution tables..
From memory around 66% fall within one standard deviation, 95 % within 2 SDs and something like 99.6% within 3 SDs.
There must be something in your course notes/text books
http://en.wikipedia.org/wiki/Normal_distributi on
These are correct values for distribution:

1 0.682689492137
2 0.954499736104
3 0.997300203937
4 0.999936657516
5 0.999999426697
6 0.999999998027

or looking at it the other way:

0.80 1.28155
0.90 1.64485
0.95 1.95996
0.98 2.32635
0.99 2.57583
0.995 2.80703
0.998 3.09023
0.999 3.29052


All you need is here with a bit of thought

1 to 2 of 2rss feed

Do you know the answer?

Microwave Oven

Answer Question >>