Technology1 min ago
Integral calculus
Hi. Struggling to remember my calculus from years ago. How do I go about integrating f(x)^n?
In this case f(x) is (g(x) + k) where g(x) is sqrt(2Rx - x^2).
Have a feeling it ends up as (f(x)^(n+1))/((n+1)f'(x)) + C?
Does that seem right?
Any help appreciated.
In this case f(x) is (g(x) + k) where g(x) is sqrt(2Rx - x^2).
Have a feeling it ends up as (f(x)^(n+1))/((n+1)f'(x)) + C?
Does that seem right?
Any help appreciated.
Answers
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No best answer has yet been selected by divlong. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.Hmmm...no - I don't think so. Because if you differentiate what you thought it was - you have a derivate of one over f'(x) to think about. If that didn't involve x, you would be ok, but in this case it does. I think you have to use the reduction formula...although I don't think it'll work completely because you've got a square root involved...I'm a bit rusty on all this though!