I have a small part of my garden which I would like to cover with coloured aggregate.
It is shaped like a right angled triangle of which the base is 400cms long(13ft), the upright 245 cms (8ft)and the hypotoneuse 460 cms (5ft). Iwould like to fill it 8cms (3inches deep) As you can tell I'm elderly which is why I'm giving both measurements as I don't really understand metric.
Can someone tell me what quanity of aggregate I'll need?
The area of your triangle is (base x height x 0.5) which equals 13 x 8 x 0.5 = 52. You want to fill that area with 0.25 ft of aggregate so you need 13 cubic feet. Or very slightly under half a cubic yard (a cubic yard is 27 cu. ft.).
The same calculation using your metric measurements is 400 x 245 x 0.5 x 8 which comes to 392 litres or 0.392 of a cubic metre.
Tooj, you'll need around 650 - 700 kg, depending on how much you may lose in the base (which I guess isn't rolled).
"Dumpy" bags contain around 800 - 850 kg. It varies slightly between merchants. They're the big ones that are craned off the back of a truck.
Alternatively, it's usually available in 25kg plastic bags..... of which you'll need 25 - 30. That way would probably work out at more than the cost of a dumpy bag, even with the bit left over.
Forget about triangles for a minute. The base x the upright wiil give the area for a rectangle. Divide the answer by two to get the size of your triangle. Then do the same here to see what quantity you'd need (it's for gravel, but will be hardly any different for aggregate)...
>Hypotenuse would be just over 15 feet, factor fiction, but don't need to know the hypotenuse to calculate amount required
Yes, I realise the hypotenuse isn't relevant to the calculation, but I wondered if the other measurements may be wrong since the other sides have to be less than the hypotenuse (as heathfield has now said0