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Lottery Odds
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You can toss a coin 50 times and each time it could fall heads up. The chances of it falling heads up the next time are still 50/50. You could toss a coin 5 million times and each time it could land heads up. The 5-million-and-1st time you toss the coin, the chances of it falling heads up is still 50/50.
It will even itself out eventually but this could take an eternity.
So, your 1st lottery ticket has a 1 in 14 million chance of winning. If it loses it has no effect on the odds of your next ticket which still has a 1 in 14 million chance of winning.
I'm pretty sure this is correct. Basically the odds on winning the lottery suck!
You are not comparing like with like Guinevere. You are correct with individual events so the chance of rolling a 6 is 1 in 6, if you roll again the chance of rolling a 6 is still 1 in 6. So if you have 1 possible set of 14m possible outcomes then yes this time you have 1 in 14m and the same next time etc. Now back to the dice, if you want to roll a 6 or a 3 then you have a 2 in 6 chance, so moving to the lottery again, if you have 2 sets of a possible 14m then you have a 2 in 14m chance ie 1in 7m.
It's pretty obvious to me that, the more tickets you buy the greater are your chances of winning.
If 14 million tickets are normally sold you would need to purchase a further 14 million yourself to have a 50% chance of a share of the jackpot. Assuming that the 14 million regulars still buy the same amount.
You would need to purchase 28 million tickets to have a 66.6% chance (you would hold 28 out of 42 million tickets) On the other hand there may be no matching tickets out of the entire 42 million.
wowo, your extrapolation goes a little wrong, as the pattern is not halving the odds each time, it is 14,000,000 divided n+1, where n is the previous number in the sequence. So it would be....
1 Ticket = 1 in 14 Million
2 Tickets = 1 in 7 Million
3 Tickets = 1 in 4,666,666
4 Tickets = 1 in 3,500,000
5 Tickets = 1 in 2,800,000
6 Tickets = 1 in 2,333,333
The absolute reduction in the odds decreases over time, so the difference to the odds of buying 1 or 2 tickets is far greater that 100 or 101.
Landie thats wrong.
The 14 million refers to the number of combinations, not the number of people buying tickets.
If only 1 person in the UK bought a ticket, they would still only have a 1 in 14m chance of winning, as that is the probability of choosing the correct numbers. No matter how many people enter the lottery, your chances of winning with one ticket are always the same.
Thats right Chazza
1 is 1 in 14,000,000
2 is 1 in 7,000,000
3 is 1 in 4,666,666 not 1 in 3,500,000 as Wo Wo claimed
To half the odds and double your chances of winning you have to buy twice the amount of tickets each time
Like i said
4 tickets is 1 in 3,500,000
8 is 1 in 1,750,000
16 is 1 in 875,000
23 Tickets only gives you a 1 in 608,695 chance of winning
32 is 437,500..........and on and on 7,000,000 million tickets give a 1 in 2 chance of winning so long as all your tickets are unique
Look, Wo Wo thinks that 23 tickets gaurentees you a win. If that was the case why dont we all go spend �23 on Sat or whenever they run it nowadays and all be Multi-Milionaires???????
The reason is that it 23 doesn't but 14,000,000 tickts does as 7,000,000 gives you a 1 in 2 chance or 50% or a very bad investment as the Lottery only pays out a fraction of the money it takes in.
You have one chance in 13,983,816 of holding the winning ticket. This probability is 0.0000000715
The more tickets you buy, the greater your chance of winning, of course.
Suppose you buy 50 tickets (which will cost you �50). Your chances of winning go up ...they're now a whopping 50 out of 13,983,816, for a probability of 0.000003575 (not much of an improvement!)
The probability of matching NONE of the six numbers is about 46.3% this means about half the time, NONE of your numbers will match!
Similarly, the probability of matching ONE of the six numbers works out to be 0.413, or 41.3% ... this is the probability of matching ONE number.
The probability of matching TWO of the six numbers works out to be 0.132, or 13.2% ... this is the probability of matching TWO numbers.
None of these results pay anything at all. If you add the three probabilities, you get 98.1%. This means that 98% of the time, you won't win anything!
The first winning ticket is the one where you match THREE numbers. The probability of this occurring (using the method above once again) turns out to be 0.018, or 1.8%, or about 2 out of 100, or about 1 out of 50. This means you must spend about �50 on average, to hope to win the �10.
Are you beginning to get the picture? Your chances of winning the big prize are next to nothing, and the chances of winning even �10 are only one in fifty.
Yet people win all the time, of course, because millions of tickets are sold every week, and somebody has to win the prizes. It's just not very likely that it will be any one person in particular (ie: you!)
But landie you say that if you buy 28 million tickets you have a 66.6% chance of winning.
If there are only 14 million possibilities then surely if you buy anything over 14m tickets (with different numbers) you have a 100% chance of winning as you have every combination of winning.
Thats where your theory falls down!