ChatterBank2 mins ago
Any One Understand Gas And Electricity Unit Prices?
30 Answers
I need to know if it is cheaper for me to heat my hot water by electric immersion heater water tank or by gas central heating for one hour.
The unit costs are:
Electricity 6.18p
Gas 2.45p
The immersion heater is 3kw.
The unit costs are:
Electricity 6.18p
Gas 2.45p
The immersion heater is 3kw.
Answers
(Last minute edit, use 31.65857 ;-) ) ------------ - I get different values for the multiplicati on factor depending on whether I use your bill's figures, or mine ! It has to be down to rounding factors I guess but ... Looking at my bill it worked out at about 31.7, but looking at the figures you give it looks more like 31.5: but I guess they are in the same ball park....
18:12 Wed 28th Sep 2016
I don't know if this is any good but have a look, https:/ /www.go ogle.co .uk/?gw s_rd=ss l#q=go+ compare +gas+%2 6+elect ricity
1166 kWhrs I suspect. (Watts are instantaneous, it costs you more to have them for a whole hour than a minute.)
Aye that fits. 1166/37 ≈ 31.7.
So whatever the question that defines it, that's the multiplier it uses to convert meter readings to kWhrs. Just take whatever gas reading increase you have noted and multiply it by that; and why it's right isn't so important.
Aye that fits. 1166/37 ≈ 31.7.
So whatever the question that defines it, that's the multiplier it uses to convert meter readings to kWhrs. Just take whatever gas reading increase you have noted and multiply it by that; and why it's right isn't so important.
(Last minute edit, use 31.65857 ;-) )
-------------
I get different values for the multiplication factor depending on whether I use your bill's figures, or mine ! It has to be down to rounding factors I guess but ...
Looking at my bill it worked out at about 31.7, but looking at the figures you give it looks more like 31.5: but I guess they are in the same ball park.
Your example where if the difference between your last meter reading and the present one, i.e. what you used, is 37, then :
37 * 31.5 = 1,165.5 kWhrs which ≈ 1166 so 31.5 seems close enough.
But using 31.7 it would have been
37 * 31.7 = 1209.9 kWhrs which ≈ 1210 which isn't as close but not that far out.
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I know what you mean about the complex equation they say they use. But it doesn't seem to me as if they use what they say they do. Let me see what my gas bill actually says regarding working it out :
meter reading (in m³)
* calories per m³ (39.2)
* fiddle factor called 'volume correction' (1.0226400)
÷ conversion to kWhs (3.6)
So... 39.2 * 1.02264 / 3.6 = 11.13541333
I don't see how they can possibly be claiming that they use about 11.
Unless .... just had a thought ... they are using a metric meter as an example and assume they read m³ directly. Whereas there are plenty of imperial meters out there reading in, well I'm not sure, cubic feet I'd suspect. So they'd need a further multiplication factor of some value.
-------------
I get different values for the multiplication factor depending on whether I use your bill's figures, or mine ! It has to be down to rounding factors I guess but ...
Looking at my bill it worked out at about 31.7, but looking at the figures you give it looks more like 31.5: but I guess they are in the same ball park.
Your example where if the difference between your last meter reading and the present one, i.e. what you used, is 37, then :
37 * 31.5 = 1,165.5 kWhrs which ≈ 1166 so 31.5 seems close enough.
But using 31.7 it would have been
37 * 31.7 = 1209.9 kWhrs which ≈ 1210 which isn't as close but not that far out.
-------------
I know what you mean about the complex equation they say they use. But it doesn't seem to me as if they use what they say they do. Let me see what my gas bill actually says regarding working it out :
meter reading (in m³)
* calories per m³ (39.2)
* fiddle factor called 'volume correction' (1.0226400)
÷ conversion to kWhs (3.6)
So... 39.2 * 1.02264 / 3.6 = 11.13541333
I don't see how they can possibly be claiming that they use about 11.
Unless .... just had a thought ... they are using a metric meter as an example and assume they read m³ directly. Whereas there are plenty of imperial meters out there reading in, well I'm not sure, cubic feet I'd suspect. So they'd need a further multiplication factor of some value.
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