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In short my dad has 87 coins made up of 1p,2p and 10ps, equal number of 1p and 10ps. If total is £3.56, how many 2ps.
I got answer by trial and error. How would you do it algebraicll or ligically plese
tia
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For more on marking an answer as the "Best Answer", please visit our FAQ.Let number of 1ps & 10ps = x (same number of each of these coins)
Let number of 2ps = y
Number of coins
x + y + x = 87 or 2x+y =87 (1)
Value of coins in pence
x*1 + y*2 + x*10 = 356
x+2y+10x = 356 or 11x + 2y = 356 (2)
You now have
(1) 2x + y =87
(2) 11x + 2y = 356
Double (1) and subtract from (2)
11x + 2y = 356 (2)
4x + 2y = 174 (1) doubled
7x + 0y = 182 now divide by 7
X = 26
So 26 + y + 26 = 87
Y+ 52 = 87
Y = 35
number of 1p coins = 26
number of 2p coins =35
number of 10p coins = 26
check
value of coins = 26p + 70p + 260p = 356p = £3.56
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