Ok, my daughter has maths homework that she can't work out (cos she was in EuroDisney when they covered it in class) and I don't have a clue. She has to work out the height of a triangle, from part way along the base to the highest angle. She has the lengths of the 3 sides (all different) and the area, but neither of us has a clue what the formula is for working it out. Any maths whizzes out there that could guide us in the right direction?
If you split the triangle in half from the top point two the bottom, you get two right angled triangles. You might be able to use pyrathagorus to work it out (or is it more likely to be triganometry?)
What are the length of the sides? any angles? if there are no angles given you should be able to use good old pythag, a^2+b^2=c^2 (but makes sure c, is the longest side, else you'll have to rearrange it slightly)
I think it'll be triganometry Molly, I have the total length of the base, but the measurement I need doesn't go to the midpoint so I then only have the hypotenuse of each of the triangles after splitting it. Thanks though :)
I seem to remember that this needs 'The Cosine Rule'(which I would have to look up or google) This will give the angles as well(I think). Once you know the lengths and angles the rest gets a lot simpler.
You have to be careful helping her as they seem to keep changing the way that kids are taught to do maths - the way my son has been taught to do 'big' multiplications is ridiculous but that's the way the school want it done.