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Working out your age by beer mathematics
32 Answers
1. First of all, pick the number of times a week that you would like to have a beer (more than once but less than 10).
2. Multiply this number by 2.
3. Add 5.
4. Multiply it by 50 - I'll wait while you get the calculator.
5. If you have already had your birthday this year add 1760.
If you haven't, add 1759.
6. Now subtract the four digit year that you were born.
You should have a three digit number.
The first digit of this was your original number (ie how many times you want to have beer each week).
The next two numbers are your age!
(Oh YES, it is!)
2. Multiply this number by 2.
3. Add 5.
4. Multiply it by 50 - I'll wait while you get the calculator.
5. If you have already had your birthday this year add 1760.
If you haven't, add 1759.
6. Now subtract the four digit year that you were born.
You should have a three digit number.
The first digit of this was your original number (ie how many times you want to have beer each week).
The next two numbers are your age!
(Oh YES, it is!)
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The number you think of initially is X
so you have
Step 1 = 2X
Step 2 = 2X + 5
Step 3 = (2X + 5) x 50 = 100X + 250
Step 4 = Add either 1759 or 1760 = 100X + either 2009 or 2010
Step 5 = subtract year of birth
Since you have a 3-digit number remaining with 100X as the leftmost digit and this year minus year of birth (your age) as the other two.
so you have
Step 1 = 2X
Step 2 = 2X + 5
Step 3 = (2X + 5) x 50 = 100X + 250
Step 4 = Add either 1759 or 1760 = 100X + either 2009 or 2010
Step 5 = subtract year of birth
Since you have a 3-digit number remaining with 100X as the leftmost digit and this year minus year of birth (your age) as the other two.
I was hoping that you'd not ask that, Mazie!
OK, here goes: Let's assume that the number of times I fancy a beer is x
Doubling it gives 2x
Adding 5 gives 2x + 5
Multiplying by 50 gives 100x + 250
Adding 1760 (for those who've already had a birthday) gives 100x +2010
Taking the age you were born from the current year (2010) reveals your age at the end of the expression. e.g. if I take 1953 away, the expression becomes 100x + 57 (where 57 is my age).
Whatever the number I started with (e.g. x =3) it will now be 100 times as big (e,g. 100x =300) at the beginning of the expression. So the first digit is now that number and the last two digits are my age.
OK, here goes: Let's assume that the number of times I fancy a beer is x
Doubling it gives 2x
Adding 5 gives 2x + 5
Multiplying by 50 gives 100x + 250
Adding 1760 (for those who've already had a birthday) gives 100x +2010
Taking the age you were born from the current year (2010) reveals your age at the end of the expression. e.g. if I take 1953 away, the expression becomes 100x + 57 (where 57 is my age).
Whatever the number I started with (e.g. x =3) it will now be 100 times as big (e,g. 100x =300) at the beginning of the expression. So the first digit is now that number and the last two digits are my age.
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