Spectator 2160

[djawhufc]

Hi all

Lavatch this week.

My business partner won first prize so my office are reigning champions.


All the best

DJA

[maurice]

Nothing worse than an under-stimulated child, Daniel!

[Jogler]

Many thanks for your continued Thursday chore, Daniel. One of the runners-up obviously had five minutes to spare!

[djawhufc]

Well done Jogler.

It will also be a surprise to my business partner I think Romy helped him out.

[barryjbutler]

Thanks Daniel but , blimey, another set of clashing cells straight after the Listener marathon!

[Jogler]

Congratulations not for us, (sadly). Someone much more illustrious!

[djawhufc]

I didn't realise- he is 'The Listener' I believe

[maurice]

Can some football fan(-atic) help me out with32d? Have ?EH?A , which I suppose is possible.
Can't see how 6a fits with the others, either (or does "regularly" mean odd/even letters?)

[Larper]

32 D. Your 'e' is wrong. And remember the last sentence in the preamble.

[maurice]

And another point: are we supposed to cram all those letters into each cell? Talk about overcrowded prisons! Or perhaps the corresponding originals?We're not all classicists..........................

[maurice]

Found this one very frustrating at the end, but think I've got it all sewn up now (incl. title, if I'm lucky: the 18 could be specially significant).

[Larper]

Maurice, glad you got finished.

[maurice]

Just one last question, larper: are you entering the characters as such, then(i.e. in the original form) ?

[mathsman]

Help,please. 3D has the correct number of letters for entry as does 12A, which seemed straightforward; yet there is a problem with the intersecting letter - which I assumed was to be a problem only when one of the words had fewer spaces for entry than the answer length. A similar quandary arises with 30D and 42A. Yet there are six other clues whose answer length does not correspond to the entry length. Am I missing something?

[Helveticus]

I am almost certain what I have to enter in the unchecked cell of 26A, which I have not solved (I have everything else), but since this cell does not intersect with a down answer, there is no clash to resolve. Any ideas?

mathsman: If there are A letters and D letters in across and down answers which clash, then you have to resolve (A + D), where 2

[Helveticus]

mathsman: If there are A letters and D letters in across and down answers which clash, then you have to resolve (A + D), where 2

[Helveticus]

mathsman: Sorry: AB keeps mangling my text. If there are A letters and D letters in across and down answers which clash, then you have to resolve (A + D), where (A + D) is a number between 2 and 6.

[mathsman]

Thanks, Helveticus, but that doesn't really answer my query.

[bibblebub]

mathsman - you've probably sussed it by now but just in case... e.g. if a clue indicates 6 letters but there are only 4 spaces in the grid then that means that 3 letters of that answer must be combined with the equivalent letters from an intersecting answer to give just one of the thematic 18, and I would assume that you must write that one thematic 18 in the intersection space in the grid (but since I don't send it in someone would need to confirm that).

[crosswhit99]

mathsman, the two clashing cells you refer to contain just 2 letters each, one contributed from each answer. These each resolve to a two-letter word/18 down. Clashes involving answers too long for their lights resolve to longer words, up to six letters.

[mathsman]

Thanks folks. Misinterpreted the preamble.