Quizzes & Puzzles1 min ago
Probability Calculation
17 Answers
I'm not sure if this question is in the right category but here goes:
Can anyone tell me how you calculate the probability of getting both lucky stars right in the Euromillions lottery for three draws in a row.
Mind you - didn't get any other number so it's done me no good!
It just seems spooky getting the lucky stars 3x in a row. But maybe the odds aren't that big anyway. Oh - and another factor - on each occasion I did 3 rows (does that affect the probability?)
I wish I had understood combinations/permutations and probability during my O-level maths years!
Can anyone tell me how you calculate the probability of getting both lucky stars right in the Euromillions lottery for three draws in a row.
Mind you - didn't get any other number so it's done me no good!
It just seems spooky getting the lucky stars 3x in a row. But maybe the odds aren't that big anyway. Oh - and another factor - on each occasion I did 3 rows (does that affect the probability?)
I wish I had understood combinations/permutations and probability during my O-level maths years!
Answers
Best Answer
No best answer has yet been selected by Barquentine. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.Just looked again and the wiki entry for the lucky stars probability was for getting no main numbers and just the two lucky stars. so yeah, ignoring the main numbers totally it's 1 in 55
11 possibilities for the first number drawn. 10 possibilities for the second number so 11*10 = 110, then because it doesn't matter what order the number are drawn in and there are only 2 numbers it's 110/(2*1)= 55
Then to get the probability of successive events it just p^n (p is the probability, n is the number of events) so in this case 55^3=166375
I used to hate stats though :)
11 possibilities for the first number drawn. 10 possibilities for the second number so 11*10 = 110, then because it doesn't matter what order the number are drawn in and there are only 2 numbers it's 110/(2*1)= 55
Then to get the probability of successive events it just p^n (p is the probability, n is the number of events) so in this case 55^3=166375
I used to hate stats though :)
Rather than purchase lottery tickets, give the money you would have invested in lottery tickets to me. I will return 51% of this money to you thereby improving your overall odds of fairing better then you would have by buying lottery tickets.
Having all ready improved your odds of fairing better then you would have by purchasing lottery tickets, in addition I promise to invest 51% of my net gains from providing this service, in lottery tickets and to give you 51% (I'm not greedy) of any winnings thus acquired, thereby, in all probability, further improving the return on your investment over simply buying your own lottery tickets . . . what a bargain! - (#783 from "1001 Get Rich Quick Schemes" by - The Schnookmeister!)
Having all ready improved your odds of fairing better then you would have by purchasing lottery tickets, in addition I promise to invest 51% of my net gains from providing this service, in lottery tickets and to give you 51% (I'm not greedy) of any winnings thus acquired, thereby, in all probability, further improving the return on your investment over simply buying your own lottery tickets . . . what a bargain! - (#783 from "1001 Get Rich Quick Schemes" by - The Schnookmeister!)
Related Questions
Sorry, we can't find any related questions. Try using the search bar at the top of the page to search for some keywords, or choose a topic and submit your own question.