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suraj123 | 16:41 Mon 10th Feb 2014 | Science
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Q.The of a cube is 1.5mm. Find its total surface area in cm sq.
Q.The opposite angles of a parallelogran are (3x-10)degrees and (2x+35)degrees. Find te measure of all the four angles of parallelogram?
--Q.The diagonals AC and BD of a parallelogram ABCD intersect each other at the point 'O'. If angle DAC=32 degrres, angle AOB=70degrees, find angle DBC.
Q.Determine the coordinates of a point on the graph of 5x-y=12 whose
(a) Ordinate is twice that of the abscissa.
(b) Abscissa and ordinate are in the ratio 3:2.
Q.Find 4 solutions of the equation 2(x+3)-3(y-1)=0
Q.Lead spheres of diameter 6cm each are dropped into a cylindrical beaker containing some water and are fully submerged. If the diameter of the beaker is 18cm and water level rises by 40cm, find the number of lead spheres dropped in the water.
--Q. The vertices of a parallelogram lie on a circle. Prove that its diagonals are equal.
Q.A cube and cuboid have same volume. The dimensions of the cuboid are in the ratio 1:2:4. If the difference between the cost of polishing the cube and cuboid at the rate of Rs. 5 per m sq. is Rs. 80, find their volumes.
Q.Construct a triangle ABC with perimeter 16cm, angle B=45 degrees, angle C=30 degrees Q.Draw the graph of lines x=3, y=4 and 2x-3y+6=0 on the graph paper. Do the lines concurrent? If yes, then find the point of concurrence.
--Q.Two circle of radii 10 cm and 8cm intersect & the length of the common chord is 12cm. Find the distance between their centres.
--Q.If the point (3,4) lies on the graph of 3y=ax+7, then find the value of a. Find the value of x when y=-1.
Q.A cloth having an area of 165 sq.m is shaded into the form of conical tent of radius of 5m.
(a) How many students can sit into the tent if a student, on an average, occupies 5/7 sq m on the ground?
(b) Find the volume of the cone.
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I'll do one for you but I think you need to try these yourself, although I'll give pointers if you wish.
1) if each side is 1.5 mm then the area of one face is 1.5 x 1.5 = 2.25mm^2.
Multiply this by 6 for the total surface area
2) hint- opposite angles add up to 180. Solve the equation 3x-10+2x+35=180 to find x. Then take it from there
Lead spheres question - Number of spheres = Volume of water rise in the cylinder / Volume of each lead sphere.
So, n = (pie.R2.h) / (4/3.pie.r2.h) = (pie.92.40) / (4/3.pie.33) = 90. Therefore the answer total number of lead spheres = 90

2) For 2 ignore mine- I misread it. Use the fact that 'supplementary' (not opposite) angles add up to 180
4) Rewrite as 2(x+3)=3(y-1)
2x+6=3y-3
2x+9=3y
y=(2/3)x +3

Then just substitute in any 4 different values for x (e.g. -3, 0,3, 6 to give integer values for y) to give corresponding y values
If you have a go at some and come back with your thoughts I think you'll get some help from here
Suraj - you should work thro these and then if you grind to a halt on one,
post it and with your solution, and we will help.
Final hint:
Regarding "If the point (3,4) lies on the graph of 3y=ax+7, then find the value of a. Find the value of x when y=-1. " Just substitute x=3 and y=4 into 3y=ax+7 and solve the resultant equation to find a
"Ask questions and get real answers from real people"
We are not electronic automatons on this site.
A modicum of common courtesy, perhaps a "please" or "thank you", would be appreciated
This is a bit like Panorama last night which highlighted immigrant students taking visa exams were given the answers by invigilators or different people taking the exam for them.

http://www.mirror.co.uk/news/uk-news/bbc-panorama-investigation-finds-english-3130112
Maybe suraj has solved these himself now as he hasn't logged into AB since he asked the question.
I think these Maths questions are good as they require a range of problem solving skills. If you do come back, suraj, I'd be interested to know where they came from. Thanks
I do not agree with answering these questons for suraj123 or any similar questions.
If these are homework, pre-exam or exam questions they are likely to be competitive versus other pupils.
If so, getting the answers off the internet is cheating.
What about those who answer as many as they can off their own bat but are beaten by suraj?
Also, I agree with Teddio - not a word of good manners.
SIQ.
one useful piece of maths would be learning how to number questions
This is about an hour's work for someone who knows what they're doing and is of no value to you apart from having the answer. One of the questions is solely a construction/drawing which we can't do for you.
Oh dear,
suraj123's first and only post. Seems like another time-waster.
Good riddance ignorant (in every way: good manners, arithmatic & maths) pest.
Note he/she can count to 3 but can he/she add them up? Rhetorical.
Oh, sorry for you factor-fiction you seem to have been suckered but well tried.
SIQ.

Sorry, grasscarp too, well tried but I guess your time was wasted and/or abused as well as factor-fiction.
Kind Regards,
SIQ.

>factor-fiction you seem to have been suckered.
Thanks for your concern, SIQ, bit I enjoy looking at questions like these and offering help or at least pointing people in the right direction and encouraging them to have a go. Yes, it's better when people say please or thank you but I've learnt to live with it after spending so much time in Crosswords
.
Dear factor-fiction,
Of course I understand your position factor-fiction. I find it natural in myself and others that when we know something or have a skill it is natural to enjoy teaching or training others,
I started on one then thought about the whole list. As I explain earlier, it just seemed fishy.
Its format just seems like a list of exam questions. If other pupils are really trying alone, it's unfair for someone to collect the answers off the internet.
Peter Pedant's approach seemed the correct one.
However I withdraw the word "suckered" and sincerely apologise to you. But I'd bet my house on it that he did not sign out because he had suddenly answered them:)
Kindest Regards,
SIQ.
Thanks SIQ. It does puzzle me why quite a few people join up, ask a question but then never seen to sign on to AB again- but maybe they forget their login details and just view and appreciate our helpful answers and feel frustrated at not being able to say thankyou

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