need imediant help with factriosing

[jp_2031]

please im desprate for help with the following sums

Factorise the following

x(squared)-7x+10

6x(squared)+x-12

i am desprate here , need to hand homework in tommrow , i cant find any1 who can help me... i would like to know how to do them , not      just the answer..please , answer asap

[Gef]

Start with two sets of brackets ( ) ( ).

To get x squared you need x times x so, (x ) (x ).

The only factors of 10 are 10 and 1 and, 5 and 2 so it now becomes (x 5) (x 2) since 10 and 1 cannot give 7.

For minus 7x you must have -5x and -2x and so it becomes (x - 5) (x - 2) which is the answer since -7 times -2 is +10.

Hope this helps and try the second one for yourself. I have the correct answer.

[Gef]

Sorry, it should have said that -5 times -2 = +10.

[fo3nix]

see this thread:

http://www.theanswerbank.co.uk/How-it-Works/Question1156 57.html

personally i think my answer is the easiest to follow, but only because that was my method ;)

[jp_2031]

thanks so much for helping , mrs kelly my maths teacher wont eat me 2morro thanks 2 u... hehe...does the 2nd one follow the same way? its jst that it has a -12 insted of a +

[Peter Pedant]

formix - is our link correct ?

i followed it for the exciting second way of factorising and found an excellent thread - with ME all over it ! On Gaussian elimination which erm is not really useful for whatever jp needs...

The second equation, jp you have to juggle 6 x2 in a similar way,

(6x +   )( x + ....) and try the factors of 12

12 and 1 and 6,2 and 3,4

in a similar way

and jp I REALLY think, you should be doing it yourself as we all clearly can do it, so it cant be hard....

AND we dont have Miss Kelly - [dan der an dan!] tomorroooooow!

goo luck 

[jp_2031]

thanks so much for helping --- im only asking on answer bank for the reasion , that all my friends in my class that ive asked dont even know how to do it.. even people in a class ahead of me dont no! ... thanks again for your replies :)   

[jp_2031]

one more thing i forgot to mention , our school is an experamental school , im in 3rd year and we are gettin standerdgrade test next summer...its usualy 4th year people get it...we got a year less than everyone ealse to learn it :( -- how unfair is that!

[Cathyhuns]

Gef's answer is only easy to solve if the factors are whole numbers.

As a general rule for any equation

ax(squared) + bx + c = 0

where a, b and c are any number the factors can always be found from the following equation

Factors =( -b +- square root of (b(squared)-4 times a times c)) divided by 2 times a

where +- means plus or minus to give the two different factors and if the bit inside the sqare root is negative then the equation cannot be solved.

PS This equation is difficult to write in text

[stevie21]

Cathyhuns, I think it's clear that the answers here are all whole numbers.

While the answer you give is correct, I think that comes later in the syllabus and may only confuse the poor dude