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Dee-M-See | 14:29 Wed 06th Sep 2006 | Quizzes & Puzzles
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Find a number
Whos half, exceeds its third, by the sum of two digits
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Avatar Image crofter
It's 54
14:32 Wed 06th Sep 2006
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Question Author
The numbers problem should read BY THE SUM OF ITS TWO DIGITS
Sorry
14:35 Wed 06th Sep 2006
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I think that the question should read "Find a two-digit number ..."

If the digits are x and y, then the number is 10x + y. The difference between one half and one third is one sixth.
Hence (10x + y)/6 = x + y (the sum of the digits)
Multiply through by 6 to get 10x + y = 6x + 6y
That is 4x = 5y.
This means that x = 5 and y = 4; and the number is 54.
14:40 Wed 06th Sep 2006
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...and presumably 'WHOSE half'.
14:47 Wed 06th Sep 2006
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Thank you both kindly for the answers and the lessons in Maths and English
Should have paid more attention in my school days
14:57 Wed 06th Sep 2006

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