Quizzes & Puzzles15 mins ago
Math Question...
13 Answers
An apprentice builds a machine, it takes him 15 hours longer than the master.
If both work together they are finished 5 hours earlier than when the master does it alone.
How long does it take for the master to build the machine on his own?
If both work together they are finished 5 hours earlier than when the master does it alone.
How long does it take for the master to build the machine on his own?
Answers
Best Answer
No best answer has yet been selected by ameriland. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.This is how you do it
Let m be the time taken by the master alone.
Apprentice takes (m + 15) hours to build a machine
so apprentice builds 1/(m + 15) machines in 1 hr
Master takes m hours to build a machine
so master makes 1/m machines in 1 hr
From the above we find that
Apprentics and master together will build
1/(m + 15) + 1/m machines in 1 hour
but we are told that apprentics and master together
take (m - 5) hours to build a machine
so together they make 1/(m - 5) machines per hour
Equating te ave two conclusions we get:
1/(m + 15) + 1/m = 1/(m - 5)
from now on it is just algebra.
(m + m + 15)/m(m + 15) = 1/(m - 5)
m(m + 15) = (m - 5)(2m + 15)
m^2 + 15m = 2m^2 + 5m -75
0 = m^2 - 10m - 75
0 = (m - 15)(m + 5)
so either (m - 15) = 0 implies m = 15
or (m + 5) = 0 which implies m = -5
In this situation, negative answers are meaningless
so m = 15 is the answer required.
Let m be the time taken by the master alone.
Apprentice takes (m + 15) hours to build a machine
so apprentice builds 1/(m + 15) machines in 1 hr
Master takes m hours to build a machine
so master makes 1/m machines in 1 hr
From the above we find that
Apprentics and master together will build
1/(m + 15) + 1/m machines in 1 hour
but we are told that apprentics and master together
take (m - 5) hours to build a machine
so together they make 1/(m - 5) machines per hour
Equating te ave two conclusions we get:
1/(m + 15) + 1/m = 1/(m - 5)
from now on it is just algebra.
(m + m + 15)/m(m + 15) = 1/(m - 5)
m(m + 15) = (m - 5)(2m + 15)
m^2 + 15m = 2m^2 + 5m -75
0 = m^2 - 10m - 75
0 = (m - 15)(m + 5)
so either (m - 15) = 0 implies m = 15
or (m + 5) = 0 which implies m = -5
In this situation, negative answers are meaningless
so m = 15 is the answer required.