x^2+(y-∛(x^2 ) )^2=1

[mollykins]

is this the equation for a line in the shape of a heart? x^2+(y-∛(x^2 ) )^2=1

I heard it was, but i'm not convinced, I might try and draw it out later, when I have more time, to see though.

[milly143]

I've never been scared by a question title until now. :o(

[yogi-bear]

Hi Molly,

Scroll down on link....it might help you. :0)

http://en.wikipedia.o...ki/Heart_%28symbol%29

[mollykins]

it doesn't match any of the ones on wiki, but it could just be in a different style.

[milly143]

*snigger*

[bibblebub]

you could use MS Mathematics http://www.microsoft....default.aspx#overview to plot it

[ChuckFickens]

I just tried that, bibble and couldn't get it to work (admittedly I only tried for about a minute)

[AB Editor]

Here you go Molly.

You should acquaint yourself with Wolfram Alpha:

http://www.wolframalp...2%88%9B(X^2+)+)^2%3D1

[mollykins]

Thanks bibble, i'm downloading it now although it's in three bits so i'm slightly confused.

[cc1]

should be possible to set up a spread sheet, input some values and then draw it out, it's not as bad an equation as it looks!

[AB Editor]

This video is a good introduction to the aims of Wolfram Alpha

http://www.youtube.com/watch?v=60P7717-XOQ

[mollykins]

Thanks ed, so it is a heart.

[yogi-bear]

Thats brilliant Ed

........Molly, you have your answer thanks to the Ed :0)

[AB Editor]

In short, yes!

[bibblebub]

Yes Chuck I found it necessary to rearrange the terms and have 2 equations, one for a positive square root and the other for the negative square root. First time I've tried it for real.

[Dris]

Yip and so does the Ed Molly :)

[jake-the-peg]

bit tricky for a spreasheet as you'll get positive and negative parts from the square root that will need to be accounted for.

The figure you're asking about is a cardioid

http://www-history.mc.../Curves/Cardioid.html

Was the answer to a University challenge question last week - bit of a coincidence!