Quizzes & Puzzles12 mins ago
Maths conundrum
9 Answers
This comes from the Past Times Puzzler Book. A young rider on a merry-go-round dreamt up this problem while enjoying his ride. One third of the number of kids riding ahead of me, added to three-quarters of those riding behind me gives the correct number of children on this merry-go-round. How many children were riding the merry-go-round. I realised you had to count in the child himself but still couldn't work it out. The answers are in the back but no explanation and I am still puzzled. Is it possible to do this sum or have they made a mistake?
Answers
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For more on marking an answer as the "Best Answer", please visit our FAQ.Let N = number of other riders
Merrygoround is circular so number in front = number behind = N
(1/3)N + (3/4)N = N + 1
LCD=12 so:
(4/12)N + (9/12)N = N + 1
(13/12)N = N + 1
multiply both sides by 12
13N = 12N + 12
Subtract 12N from both sides
N = 12
So there are 12 other riders and with the person themself that makes 13 all together.
Merrygoround is circular so number in front = number behind = N
(1/3)N + (3/4)N = N + 1
LCD=12 so:
(4/12)N + (9/12)N = N + 1
(13/12)N = N + 1
multiply both sides by 12
13N = 12N + 12
Subtract 12N from both sides
N = 12
So there are 12 other riders and with the person themself that makes 13 all together.