grade ten math

[jodiiss]

Sovle the following systems by substitution
(show ALL the steps please)

a) y=6-x
y=x+3


b) x=y-5
x=3y+13


c) 3x+y=2
2x+y=13

d) 2x-3y=-7
2x+3y=11

e) x-y = -5
2x-y=-7

f) 4x+3y=-9
-4x+y= -19




Solve part (G) by substitution and part (H) by elimination,
(again please show all steps)

g) x+5y= -17
3x-4y=6


h) 9x+2y=2
4x+y=1

[Tichfield]

Are we doing your homework for you?

:-))

[Tichfield]

a)

Substitue (6-x) for y in y=x+3

So 6-x=x+3

So 2x= 3

So x=1.5

So y=1.5+3

So y=4.5


Do the rest of them using the same method.


If this is grade 10 maths that's 14/15 year olds isn't it?

I was doing this at ahe 8/9.

[Tichfield]

At age 8/9.

[kempie]

My first is in home but not in work
My second is in answer but never in shirk
My third is in attempt and also in try
My last is in truth but not in a lie

[jodiiss]

thanks :)

[NewDazzler]

Tichfield, you are right about the age, but remember nowadays the poor students may have to do 2 exams in one day, although I guess having cheated on their coursework to get about 50% of the marks already may have helped a little.