Crosswords0 min ago
Engineering Science
If anyone can help with my last assignment question please.
A car accelerates along a straight road with a uniform acceleration when it passes A it has a speed of 12m/s and when it passes B it has a speed of 32m/s. points A and B are 1100m apart. Determine the time taken to move from A to B.
Thanks in advance
David
A car accelerates along a straight road with a uniform acceleration when it passes A it has a speed of 12m/s and when it passes B it has a speed of 32m/s. points A and B are 1100m apart. Determine the time taken to move from A to B.
Thanks in advance
David
Answers
using the equations
v^ 2 = u^2 + 2as and v = u + at, where u=initial speed, v=final speed, a=accelerati on, s = distance travelled and t=time and rearranging,
you get
t = 2s / (v+u)
=2200/44
= 50 m
you get
t = 2s / (v+u)
=2200/44
= 50 m
23:17 Sat 23rd Jun 2012
I agree with you entirely factor. I was just trying to point out to Ignoblius where the flaw in his argument lies.
It's easy to see that he is wrong because his formula for the time difference does not depend on the initial velocity, but only on the difference between the initial and final velocities. So if the initial velocity were 1,000,000 m/s and the final velocity 1,000,020 he would get the same answer, which is obviously wrong!!
It's easy to see that he is wrong because his formula for the time difference does not depend on the initial velocity, but only on the difference between the initial and final velocities. So if the initial velocity were 1,000,000 m/s and the final velocity 1,000,020 he would get the same answer, which is obviously wrong!!