maths question (part deux)

[*mystical*]

Here is the real question:

Draw the graph to solve the equations simultaneously

x^2 + y^2 = 2   y = 2x - 1

Thanx

xx

[Personica]

I don't totaly understand your meaning of "Draw a graph".

As both equations provide thier own solutions, there can only be one plot point, therefore, it wouldn't be a true 'graph'

If your question is what does x and y represent, the answer is x=1, y=1

[secretsquiz]

also, wouldn't it be more constructive to do your own homework?

[jake-the-peg]

What you need to do is to draw both graphs on a piece of paper  [ hint: you'll probably need to adjust the first to say y= sqrt(.....) ]

Where these two graphs cross you can read off the x and y values where the equations are simutaneously true.

Summary - draw both graphs - see where they cross - write down x and y of where they cross - feed back into equation to check.

Easy

[newtron]

Graph each equation and the solutions are the points where the two curves intersect. 

[*mystical*]

secretsquiz - I have attempted this question for many hours. I always do my own homework unless I am stuck, then I need some help....!!??

[fo3nix]

draw both graphs on the same exes. At certain points, they will intersect (the lines will cross over).

These points are the solutions to both equations. Then look at your graph's axes to find the x and y values, and you have values of x and y.

Of course, you could just solve the equations simultaneously and forget drawing the graph. But I guess that's part of the homework too ;)

[jake-the-peg]

Don't worry Mystical it's just some people get lazy with their homework if you want a laugh go to science a post a question about heating up a brick to 1500 degress [don't though there'll be major tantrums :c) ]

Simultaneous equations represent two sets of formulae say the x and y co-ordinates and time of two billiard balls on a table.

when the x y and t are all the same in both equations the balls will collide ( OK that example has an x, y and a t for the time too but I hope you get the picture).

Now by solving the simultaneous equations either by algebra or by a graph you see when and where ( or if ) the balls will collide.

Hope that helps if not please feel free to ignore.

[jean88]

just draw x^2 + y^2 as a circle graph

[*mystical*]

awwww thanks people who actually helped... or at least tried...much appreciated

Shout out to:

kempie (from previous post)

Personica

jake-the-peg

newtron

fo3nix

jean88 (she was rite)

well i guess dats everyone on here. . . lol

thanx peeps again

[secretsquiz]

sorry mystical. didn't mean to cause offense, but as jake-the-peg points out there are lots of questions on here along the lines of i-can't-be-bothered-to-do-my-own-work.

the fact that you simply quoted the problem suggested that your question was one of them.

apologies.

[*mystical*]

ok secretsquiz as u can see from your ''3 star answer'' i have exepted your apology lol

xx

[Tim123]

x^2 + y^2 = 2 Is a circle, radius sqrt(2) centred on the origin
y = 2x -1 is a straight line that crosses the x axis at -1 and the y axis at +1/2
The solutions are where these lines cross