Crosswords0 min ago
Biology Help
A woman who does not carry an allele for color-blindness marries a man who is color-bling.
1. What is the genotype of each parent?
2. How many of their female children will be carriers?
3. How many will have the disease?
4. How many of their male children will have the disease? draw a possible pedigree for this scenario (show the carriers).
A woman with normal vision marries a normal man. They have three girls with normal vision, one boy with normal vision, and a color-blind boy.
1. What is the genotype of each parent?
2. Draw a pedigree for this scenario.
A woman has a father with hemophilia and a mother who is normal.
1. What is the woman's genotype?
2. If she marries a normal man, what are the chances that she will have a son that has hemophilia?
1. What is the genotype of each parent?
2. How many of their female children will be carriers?
3. How many will have the disease?
4. How many of their male children will have the disease? draw a possible pedigree for this scenario (show the carriers).
A woman with normal vision marries a normal man. They have three girls with normal vision, one boy with normal vision, and a color-blind boy.
1. What is the genotype of each parent?
2. Draw a pedigree for this scenario.
A woman has a father with hemophilia and a mother who is normal.
1. What is the woman's genotype?
2. If she marries a normal man, what are the chances that she will have a son that has hemophilia?
Answers
1 to 12 of 12
AFAIK If a mutation is carried on the X chromosome you'd need a double factor in girls and a single factor in boys for it to be active. (ignoring some extraneous factors). In your first example all the daughters will receive one factor for CB, so will be carriers. As the mother is not a carrier all sons will be without any CB factor, so normal. The second example the...
05:43 Thu 19th Jan 2017
AFAIK If a mutation is carried on the X chromosome you'd need a double factor in girls and a single factor in boys for it to be active. (ignoring some extraneous factors).
In your first example all the daughters will receive one factor for CB, so will be carriers. As the mother is not a carrier all sons will be without any CB factor, so normal.
The second example the mother must be a carrier as one son has the mutation. Half of the daughters will also be carriers.
Third example The woman is a carrier and so passes the mutation gene to half of her sons (Only one of her two X chromosomes are passed to the sons) that will have Hemophilia.
I've probably made some errors but I'm someone more learned will come along soon to amend.
You can do the genotyping and pedigree yourself, it is easy.
In your first example all the daughters will receive one factor for CB, so will be carriers. As the mother is not a carrier all sons will be without any CB factor, so normal.
The second example the mother must be a carrier as one son has the mutation. Half of the daughters will also be carriers.
Third example The woman is a carrier and so passes the mutation gene to half of her sons (Only one of her two X chromosomes are passed to the sons) that will have Hemophilia.
I've probably made some errors but I'm someone more learned will come along soon to amend.
You can do the genotyping and pedigree yourself, it is easy.
-- answer removed --
// If they feel they shouldn’t answer the question because it is homework, the solution is simple. Don’t answer. //
and Nigh is so busy damning people, she hasnt answered any part of the question herself but that doesnt prevent our Ni from posting
Dink - read your chapter on X linked conditions !
// A woman has a father with hemophilia and a mother who is normal.
1. What is the woman's genotype?
2. If she marries a normal man, what are the chances that she will have a son that has hemophilia? //
1. the woman is an obligate carrier - the difficulty about telling you the answer is that you dont really learn anytiing
2. ( answered as if it reads: what are the chances that if she has a son then he will be haemophiliac - one half.
The chances of having a son are one half so the overall chance is one quarter - but I dont think your teacher is asking that )
and Nigh is so busy damning people, she hasnt answered any part of the question herself but that doesnt prevent our Ni from posting
Dink - read your chapter on X linked conditions !
// A woman has a father with hemophilia and a mother who is normal.
1. What is the woman's genotype?
2. If she marries a normal man, what are the chances that she will have a son that has hemophilia? //
1. the woman is an obligate carrier - the difficulty about telling you the answer is that you dont really learn anytiing
2. ( answered as if it reads: what are the chances that if she has a son then he will be haemophiliac - one half.
The chances of having a son are one half so the overall chance is one quarter - but I dont think your teacher is asking that )
1 to 12 of 12
