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G C S E Loci Question

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kuiperbelt | 15:43 Mon 10th Apr 2023 | Science
29 Answers
The link below shows a recreation area open to the general public.

A park bench is to be installed under the following constraints:

i. The bench is to be equidistant from point B and from point D
ii. It is to be exactly 75 metres from point C

Using a ruler and pair of compasses only.
Mark the point with an X where the bench will be situated.
All working must be shown.

https://ibb.co/422yBm7
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Unless more information about the scale is given, this problem does not lend itself to being solved online. The scale in question is only meaningful to a hard copy. Had the diagram been accompanied by a standard guage (as seen on a map), a straight line of fixed length eg. _____ = 1 cm then this would have adjusted itself automatically in direct proportion to the...
14:37 Tue 11th Apr 2023
Construct a perpendicular bisector for points B and D, a circle centred on point C. I am not going to do this, but eyeballing it looks like it will end up fairly close to A.
But we don't know the scale.
So we don't know the radius from C.
But the person who's doing this question will have it down on his paper and so presumably will be able to follow Clare's advice.
I think I got there in the end. Clare explained the method.
But Clare's eyeballing; I'm not so sure.....
The scale is on the drawing so the radius from C is 7.5 cm
Prudie; the scale is 1cm = 10m. But my computer screen doesn't let me stick a ruler up to it.
But, Clare's method is sound.
I don't think we can do it on a computer screen, I assume you need the actual test paper to draw on but yes the method is fairly obvious.
I'd guess that the image as shown is (more or less) actual size. As to whether I properly eyeballed a 7.5cm-radius circle, hard to say -- probably I've overestimated how large it would be.
But if I open this drawing on my phone it's a completely different size to my tablet and laptop. Whatever.
Is it acceptable to judge the perpendicular just by eye?
The exact answer isn't really relevant, the method is what counts here.
If the length of one of the sides were known, it would be possible to provide an answer.
// But if I open this drawing on my phone it's a completely different size to my tablet and laptop. Whatever. //

Obviously, my laptop screen represents the ideal and actual size of all images it displays, duh.

(Alternatively, I'm a moron.)
I wondered if might on A4 paper and whether the four pairs of right-angle lines were in the ratios used for A sizes but they're not.
I guess that we should presume that the person attempting the problem would be using a printed sheet at the right scale. The question should really have provided a proper scale as part of the diagram.
There is a scale but without the measure of at least one of the sides, it's not possible to show where the "X" should be.
TCL; by scale I meant a picture of a line calibrated with cm markings so that dimensions can be read whatever the variations in printing.
The whole point of the question is to use a compass to make a perpendicular line half way between B and D and then draw a circle of radius 7.5 cm with its centre at C to show the point on your drawing where they cross. That's where the bench should be. It's not about calculating, it's about using a compass.

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