ChatterBank3 mins ago
quadratic equations help
12 Answers
ok i was doing a few quadratic equations examples for revision...and i came across some that im not totally sure how to do...can someone please explain??
one is:
solve this quadratic equation: x (x+4) = 0
the other one is:
rearrange into the form 'x^2 + bx + c = 0' then solve by factorising:
x + 4 - 21/x = 0
i hope thats clear enough...thanks (:
one is:
solve this quadratic equation: x (x+4) = 0
the other one is:
rearrange into the form 'x^2 + bx + c = 0' then solve by factorising:
x + 4 - 21/x = 0
i hope thats clear enough...thanks (:
Answers
Best Answer
No best answer has yet been selected by tiger~torah. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.It's a long time since I did algebra, but this is how it goes I think!
everything you do to one side you must do to the other.
So start by multiplying out the left side & you get x2 (don't know how to right squared) +4x = 0
Then take the 4x from both sides. (x2 = -4x)
Then divide both sides by x (x2/x = -4)
SO x = -4
Hope that helps.
Sorry don't remember how to do the other one!
everything you do to one side you must do to the other.
So start by multiplying out the left side & you get x2 (don't know how to right squared) +4x = 0
Then take the 4x from both sides. (x2 = -4x)
Then divide both sides by x (x2/x = -4)
SO x = -4
Hope that helps.
Sorry don't remember how to do the other one!