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Cocaine in the flour?

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Yeah Bee | 21:03 Tue 14th Dec 2004 | Quizzes & Puzzles
7 Answers
The London antidrugs squad gets a tip that a shipment of flour contains one kg of cocaine. The cocaine is inside on of the bags. The  15 bags of flour weighs 100kg each plus one has got an extra kg. You have an scale weight but can only weigh  the bags two times, How do you find the cocaine? Can't break the bags
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The antidrugs squad can't break open a few bags of flour to find cocaine that they know is in there? For a supposed logic puzzle, that's one of the least logical things I've ever heard.
Bring out the sniffer dogs.

Are you sure it is only 2 times and not 3 times?  If it is three, the answer is:

 

Weight bags 1-6 against bags 7 -12.  If they match then it is in one of bags 13-16.  Weigh 13-14 against 15-16, and then either 13 against 14 or 15 against 16 depending which was heavier. 

If 1-6 against 7-12 does not balance, assume that it is 1-6 that is heavier.  Weight 1-3 and against 4-6.  Assume that it is 1-3 that is heavier.  Weigh 1 against 2.  If they balance, it is 3, if they don't. it is whichever is heavier.

 

If you can do it in 2 weighings. let me know!

Question Author

First you weigh bags 1-3 against 4-6 if they are even you weigh 7 against 8 if they are even the 9:th is the one with an extra kg. Likewise if 1-3 is heavier then 4-6 you weig 1 against 2 if hte aren't even you got it

So two times

three bags against three bags then one against one 

Question Author

First you weigh bags 1-3 against 4-6 if they are even the coke is in bags 7-9, you then weigh 7 against 8 if the are even you got the coke in bag nr 9.

So two times

three bags anaisnt three bags then one on one

Yeah Bee, you answer covers 9 bags, but you said there were 15!  What happened to bags 10-15?
Question Author

It was a trick question!!!

No acctually my fingers worked faster then my brain, I am so embarresd,

You certainly need luck to do it in two.

My mistake, sorry the puzzle should be about 9 bags of flour

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Cocaine in the flour?

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