Donate SIGN UP

Among the halides F,Cl,Br and I, Flourine is considered to be the most electronegative. So, considering the solutions; HF(aq) and HCl(aq), which is more acidic and why?

Avatar Image
titanium_micky | 19:42 Thu 04th Mar 2010 | Science
3 Answers
Electronegativity of course is greatest among the elements on the far right of the periodic table than the alkaline and alkaline earth metals on the far left. it is a periodic property which increases across the period but decreases down the group. For a solution of aqueous hydrogen fluoride, because fluorine is more electronegative than Cl, so in the bond formation with its hydrogen atom, it pulls the hydrogen closer soo much to itself that the atomic radius is very very small. the inability of hydrogen to break free and dissociate in the water to bring about acidity causes a solution of HF(aq) to be less acidic...but in the case of HCl(aq) Cl has an electronegativity which is less, as compared to F, hence although it forms a covalent bond with hydrogen, it is able to release hydrogen in aqueous solutions to bring about free mobile electrons for acidity.the bond or atomic radius is hence larger than in HF.
Gravatar

Answers

1 to 3 of 3rss feed

Best Answer

No best answer has yet been selected by titanium_micky. Once a best answer has been selected, it will be shown here.

For more on marking an answer as the "Best Answer", please visit our FAQ.
Goodness me. Is there a question?
I can't work out why titanium_mickey is answering his own questions today.
Question Author
i felt lyk answering my own questions today, thanx a lot, factor 30...but will still lyk to hear ur opinions on anything, thnx

1 to 3 of 3rss feed

Do you know the answer?

Among the halides F,Cl,Br and I, Flourine is considered to be the most electronegative. So, considering the solutions; HF(aq) and HCl(aq), which is more acidic and why?

Answer Question >>

Related Questions

Sorry, we can't find any related questions. Try using the search bar at the top of the page to search for some keywords, or choose a topic and submit your own question.