Quizzes & Puzzles0 min ago
probability poser
Which is more likely:
a) everyone took a wrong shirt; or
b) at least one person took their own shirt ?
I believe it is b) but I can't explain why.
Any brief explanation would be appreciated.
Answers
No best answer has yet been selected by merlinmynx. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.I know a way to figure this out but my batteries in my calculator would run out or id still be pressing buttons next Julember...
So if anyone can tell me a formula to find the sum of (0.99)x(0.99+0.98)x(0.99+0.98+0.97)x...x(0.99+0.98+...+0.01+0.00) then I can definitely tell you but I don't know how to find the sum of a non-aritmetic series.
Hi Jenstar. I would have thought so too but the probability for two people isn't (1/2)^2 (= �), it's � ; for three people it's not (2/3)^3 (= 8/27), it's 2/6; and for 4 people its not. (3/4)^4 (= 0.316�), its 3/8 (= 0.375) (
http://www.theanswerbank.co.uk/Quizzes-and-Puzzles/Quest ion87877.html) So I don't think the formula willl work for 100 people either.
Hi merlinminx. I too was following magicdice's advice and found you had got here before me. If you have to produce an answer on what you have at the moment you could still suggest that (99/100)^100 (=.0366..) is a reasonable-sounding approximation even though you know it's not the exact answer. Let us know if you find out what that is, please.
The first thing to note about this question is that the two possible answers are mutually exclusive - that is, answers a and b cannot both be true at the same time. Furthermore, a and b are opposites of each other in terms of probability, i.e. the probability that a is true must be 1- (one minus) the probability that b is true. If probability (a=true) is 0.3 then probability (b=true) must be 0.7.
The probability that everyone takes a wrong shirt can be logically deduced quite easily, and I believe the answer is 1/100, i.e. 0.01.
To prove this to yourself, consider the first person to take a shirt. Of the 100 shirts, 99 are not his (or hers). The probability of taking a wrong shirt is therefore 99/100. The second person sees 99 shirts, 98 of which are not his, so his probability is 98/99. This continues until just 2 shirts remain. The probability that the 99th person picks the wrong shirt is 1/2. (The 100th person is ignored because there is only 1 shirt left at this stage.) The calculation goes:
(99/100) x (98/99) x (97/98) ... (3/4) x (2/3) x (1/2)
[continued]
If this series was written as a single fraction, it would go:
(99 x 98 x 97 ... x 3 x 2 x 1) / (100 x 99 x 98 ... x 4 x 3 x 2)
Notice that the bottom line of the fraction is almost exactly the same as the top, but just one number out of step. This allows all the 99s to be cancelled, all the 98s to be cancelled, all the 97s...all the 4s, all the 3s and all the 2s. In fact, everything cancels out except the 1 and the 100, leaving the final probability as 1/100. Since a and b are opposite, the probability that at least one person took their own shirt is 99/100.
Net squirrel has alittle fault in his answer.
The first person to pick has 100 sweaters to choose from, 99 of which are not his. Therefore has a 99/100 chance of not picking his own.
The second person has 99 sweaters to choose from. All 99 may not be his (i.e. the first person may have picked it already). He may have a 99/99 chance of not picking his own or a 98/99 of not picking his own.
The rest of the logic seems sound
I agree with Jenstar 'By the time that, say, person no.32 comes to pick a shirt, their shirt might not even be in the pile anymore, which would mean their chance was not 1/68, but zero.'
And I took this into consideration before my first answer, which is why i couldn't find an answer because the working would take far too long and formulae (there must be some) would be needed to prove a correct answer without sitting pressing buttons all day.
Also with the amount of buttons that need to be pressed on the calculator means that the probability of finding the correct answer would be very high!
Brilliant, cuan2002! I attempted the same method but I counted 70 ways for b to be true instead of the correct 72, which kind of messed things up. Your answer appears to be the first correct one!
However, the solution still remains to be worked out through logic and thought, rather than trial-and-error. It's a real bug*er to do.
The problem that you have posed is a version of the misaddressed letter problem that was posed by Niclaus Bernoulli.
With two people, the probability of getting the wrong sweatshirt is 1/2, for three people it is 2/6 and for four people it is 9/24. The general formula for the probability of n people all getting the wrong shirt is:
1/2! - 1/3! + 1/4! - 1/5! + 1/6! ... + 1/100!
The probability methods discussed fail because the probabilities do depend on each other, as jenstar says. A listing method is tedious but does generate the first few cases easily enough e.g.
person A B
s/shirt a b i.e. 1/2 where all are wrong
b a
person A B C
s/shirt a b c i.e. 2/6 where all are wrong
a c b
b a c
b c a
c a b
c b a
The problem is in 'The Penguin Book of Curious and Interesting Puzzles' and probably other places as well.