Wrong place to put this but there are no maths sections

[amazingtoxic]

Can anyone tell me how to factorize

x2-7x+10

Thanks

[Gef]

(x-5) (x-2)

[Bohne]

I guess it's x^2-7x+10

Then you use the 'midnight formula':

[ x^2+ax+b => x=a/2+-(square root of)(a^2/4-b) ]

x=7/2+-(square root of)(49/4-10)
=7/2+-(square root of)(9/4)
=7/2+-3/2

So you get two solutions 5 and 2 and therefore factorized:

(x-5)(x-2)

[CT]

For an eqn like this you can try out values in your head. eg. the last number must be a mutliple of the non x terms in the answer. 10 is divisble by itself and 1 and also 2 & 5. 2 & 5 or 1 & 10 must make up the middle term in the eqn. Since only 2& 5 can do this, they must be the solutions. As shown below by Gef.