Shell Script (Unix) Help Please.

[xAsh]

I am trying to write a script whereby i ask a user to input a number and then output a table of multiplication for the number given. So if "6" was entered, it would print out:

1x6=6
2x6=12
3x6=18
4x6=24
(up to 10 x the number input).


I've created other shell scripts but i just cant get my head around this.

I've got so far:

#!bin/ksh
echo "Enter a number"
read number


Thats it, im finding this really difficult lol. I dont know if any let, read, if, then or else, case statements needed. Any help please?


tnx

[fo3nix]

(I can't remember bash shell syntax.)

for (i=1; i<11; i++) {
echo i + "x" + number + "=" + (i * number)
}

[whiffey]

W "enter number "
R n
F i=1:1:10 D
.W n," times ",i, " = ", n*i,!
.Q
Q
; or similar

[xAsh]

k cheers.

when i do :

#!/bin/ksh
for (i=1; i<11; i++) {
echo i + "x" + number + "=" + (i * number)
}

it says theres an unexpected at line 4 with the brackets?

why is this? tnx

[fo3nix]

I don't know if that's the correct syntax. Treat it as pseudo-code. The correct syntax is probably more like whiffey's example.

[whiffey]

This will do it, but lol I haven't done any shell scripting for quite a while !

#!/bin/ksh
echo "Enter number: "
read number
let x=1
while [[ $x -lt 11 ]]
do
let mult=number*x
echo $x "times" $number " = " $mult
let x=x+1
done

There are other ways (of course being Unix)

for i in 1 2 3 4 5 6 7 8 9 10
do
echo $i
done

The language I gave the previous answer in is one called M (MUMPS). It is absolutely brilliant and I use it all the time (on a Solaris platform) in preference to shell or perl for all general purpose data manipulation.