ChatterBank5 mins ago
the great escape
Imagine (this may be hard) that I'm in Essex in my Fiesta 1.1LX. I want to leave badly, but don't have money for the dartford crossing, so I decide that (with certain modifications) I want to jump the Queen Elizabeth II bridge to miss the tolls. How fast would I have to be travelling (I realise my car doesn't go this fast, but let's say it's powered by a jet engine)?
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As the QEII bridge is 2.8 kilometres long according to this website http://www.dartfordarchive.org.uk/technology/commu
nication_drc.shtml and taking your fiestas wieght as a standard 874 kilos (you don't specify the year so I'll have to guess at this one) then with a take off ramp at an angle of say 45� then you can use he equations on the following pages to work it out for yourself....
nication_drc.shtml and taking your fiestas wieght as a standard 874 kilos (you don't specify the year so I'll have to guess at this one) then with a take off ramp at an angle of say 45� then you can use he equations on the following pages to work it out for yourself....
http://www.usafa.af.mil/dfp/cockpit-phys/md2th2.ht
m
http://webphysics.iupui.edu/152/152sp03/152Basics/
projectiles/projectiles.html
http://www3.district125.k12.il.us/faculty/tgraba/A
ccelerated/projmotioneqs.html
I'm not going to do all the hard work for you....Good Luck
You got me to thinking though and I tried a few figures out....It's really not an easy thing to work out exactly as physics equations tend to ignore things like wind resistance and other variables and only include constants like gravity (9.81 m/s/s) but i came up with a rough estimate of somewhere in the region of 420-450 miles per hour for a take off angle of 45 degrees....I stand to be corrected on this by anyone with a better working knowledge of the equations though.