algebra help

[shortstuffO3]

Yeah I need some help for all you really good algebra people. I have this problem and I really forget how to do it. I am not quite sure if it is Science, but here it is. The length of a rectangle is 2 feet more thatn twice the width. The perimeter is 34 feet. Find the dimensions of the rectangle. If someone could give me the equation for that, that would be a great help. Thanks!

[gen2]

let width = w
so length = (2w + 2)

perimeter = 2(length + width)
= 2( w + (2w + 2) )
= 2( 3w + 2 )
= 6w + 4

Equate that to the perimeter given and solve for w

[shortstuffO3]

Thanks you were a bunch of help and seem to know what you are doing. So I have 2 other questions that I am not sure about so if you wish try them: 1. Write as an equation: The sum of y and the cube of n is 6 less than the square of v. 2. This is a proportion: 7/9 = x+3 / 4-x

Anyone who can solve that I need help!!!

[kempie]

Q1 is a case of translating the the words into mathematical notation.

The first half of the eqn is y + n� =

(... complete the other half)


Q2 needs both sides of the eqn to be multiplied by the denominators thus

9 * (4 - x) * 7/9 = 9 * (4 - x) * (x + 3) / (4 - x)

7 (4 - x) = 9 (x + 3)

(... work through to find x)