si

[sambob]

What is the SI of A when

A= square root of (hc divided by G)

Whereby SI unit of h is J
SI of c is m s-1
SI of G is J m Kg-2

[bernardo]

I reckon it's
kg s^ -1/2

[Peter Pedant]

Yeah so do I, this a straighforward dimensional analysis thingey.

A is J m s-1 over J M kg-2

Js and Ms cancel so you dont even have to worry about that a J is - ML2T-2 in case you were wondering

This leaves you with M2/T

take a sqr

and this should as B says give you kg per root sec.
and the dimension is MT-1/2

or womething, anyway on those lines

[mibn2cweus]

(PM) = Planck's mass = √ hc/G = ~ 2.17645 � 10-8 kg

[TTG]

Totally wrong.

SI= A-c (m-1) where as SI=J-kg+2+h+j

Easy.