Number

[Dee-M-See]

Find a number
Whos half, exceeds its third, by the sum of two digits

[crofter]

It's 54

[Dee-M-See]

The numbers problem should read BY THE SUM OF ITS TWO DIGITS
Sorry

[crofter]

I think that the question should read "Find a two-digit number ..."

If the digits are x and y, then the number is 10x + y. The difference between one half and one third is one sixth.
Hence (10x + y)/6 = x + y (the sum of the digits)
Multiply through by 6 to get 10x + y = 6x + 6y
That is 4x = 5y.
This means that x = 5 and y = 4; and the number is 54.

[Quizmonkey]

...and presumably 'WHOSE half'.

[Dee-M-See]

Thank you both kindly for the answers and the lessons in Maths and English
Should have paid more attention in my school days