I'd start same way as last time.
The numbers 1 to 21 add up to 231. Divide by 7 thats 33 I think. So each triplet must add up to 33
Then list the triangle numbers 1,3, 6, 10, 15, 21, 28 etc and arrange in blocks of 33
. I'm not sure thats going to work now though.
maybe I misundastood as I cant find any way's a getting 3 of them numbers to add up to 33... unless I need 2 pairs of triplets that add up to 66 but am too tired
Ignore mine.... its the numbers from the list 1 to 21 that have to be grouped and added to give traingular numbers.... I was wrongly adding triangular numbers. My bad
If it helps anyone google says the first triangular numbers are
I think you use the numbers 1 to 21 so if you used 2,3 and 5 that would up up to 10 which is a triangular number but you wouldnt be able to use those three individual numbers again. But you could use a different three which would make a different triangular number. You have to use all 21 nubers i think and come up with 7 griups of three
Its not the triplets tha as to be a triangle number, its the sum of two triples
so find 6 numbers from the list1-21 that add up to 66 which is trianguler. Say 1,2, 6 and 20, 19, 18
Then look for others and swap and change as needed.
Enjoy, am off to bed