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6 Answers
Neighbour and his Dad possess 2 x 2500 Watt loudspeakers
with built in Amplifiers. He believes on max output they would draw
nearly 20 Amps each. He is afraid this will trip the 32Amp ring breaker.
Someone please advise.
with built in Amplifiers. He believes on max output they would draw
nearly 20 Amps each. He is afraid this will trip the 32Amp ring breaker.
Someone please advise.
Answers
1 to 6 of 6
On the proviso these are 240 volt active loudspeakers as opposed to being passive, the liklihood, 2500 Watts is the peak power rating. However, let us look at the instance where the continuous power rating (rms) of the loudspeaker is 2500 Watts. Assuming 8Ω impedance, current flowing through the speaker coil √(2500/8) approximates to 18 Amps. Add on...
17:22 Tue 18th Apr 2023
Hymie is correct regarding BS1363 type cartridge fuses.
Below is a 2500W (built in amp) speaker. If you scroll to the specs, You'll see that it only consumes 1100W
Therefore: P / V = 1100W / 230V = 4.78 A
I am not an electronics expert, But I would hazard a guess that the consumption of the setup would be approx the same. So with both functioning at full capacity, You would be looking at a draw in Current of about 10A max.
Get some earplugs kuiperbelt ;-)
Below is a 2500W (built in amp) speaker. If you scroll to the specs, You'll see that it only consumes 1100W
Therefore: P / V = 1100W / 230V = 4.78 A
I am not an electronics expert, But I would hazard a guess that the consumption of the setup would be approx the same. So with both functioning at full capacity, You would be looking at a draw in Current of about 10A max.
Get some earplugs kuiperbelt ;-)
On the proviso these are 240 volt active loudspeakers as opposed to being passive, the liklihood, 2500 Watts is the peak power rating.
However, let us look at the instance where the continuous power rating (rms) of the loudspeaker is 2500 Watts.
Assuming 8Ω impedance, current flowing through the speaker coil √(2500/8) approximates to 18 Amps. Add on another 2 to 3 Amps for ancillary circuitry, then rounding up, we arive at 20 Amps (your neighbour's reckoning). Doubling up gives 40 Amps for the two speakers.
It must be remembered this is the current derived from the the secondary circuit of a mains transformer. It would not be unreasonable to suggest a 2:1 step down mains transformer in each active loudspeaker. This results in 10 Amps flowing in the mains fed primary circuit of each transformer.
Therefore the 32Amp breaker on the ring main (handling 20 Amps) will comfortably operate without tripping. Conventional 13Amp plug more than adequate.
However, let us look at the instance where the continuous power rating (rms) of the loudspeaker is 2500 Watts.
Assuming 8Ω impedance, current flowing through the speaker coil √(2500/8) approximates to 18 Amps. Add on another 2 to 3 Amps for ancillary circuitry, then rounding up, we arive at 20 Amps (your neighbour's reckoning). Doubling up gives 40 Amps for the two speakers.
It must be remembered this is the current derived from the the secondary circuit of a mains transformer. It would not be unreasonable to suggest a 2:1 step down mains transformer in each active loudspeaker. This results in 10 Amps flowing in the mains fed primary circuit of each transformer.
Therefore the 32Amp breaker on the ring main (handling 20 Amps) will comfortably operate without tripping. Conventional 13Amp plug more than adequate.
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