I Wonder Why This Number Is Rising So...
Politics0 min ago
No best answer has yet been selected by Bonzo 2000. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.The birds' weight would not "be transferred through the air"; you can check this by placing something light (so you don't break your equipment) on a pair of scales, then lifting it up and dropping it onto the scales - it will only register the weight when the item touches the scales (or possibly fractionally before due to air pressure).
To sum up the agruments above: the truck remains the same weight, but if you were to weigh the truck and the birds and compare it to the weight of the truck with the birds in flight, the second weight would be lighter.
Thats true, to an extent. The molecules of gasses being moved by the birds' wingstroke would exert some pressure on the floor of the container, but this would dissapate relative to the distance the wings are from the floor. some molecules would change direction enough to be going horizontally and would exert their pressure on the sides of the container so their 'weight' would be pusing outwards rather than downwards.
None of this takes account of the period of time that the truck weighs more because of the birds take offs/landings.
So the answer is that the truck would be marginally lighter with the birds in flight than with the birds at rest varying dependant upon the height of each individual bird in flight, it's position in it's wingstroke and the volume of gasses that they are conatined within and the randonmess of the directions that the gas molecules are taking when they make contact with the container flor/walls/roof as a result of the wing movement (note the walls, like already said, if it was open sided then there would be a greater degree of randomness to the 'weight'.
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