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No best answer has yet been selected by OBonio. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.Yes indeedy there is a number .9 recurring, and its one!
( take .9 from one, then take .99 from one, then take .999 from one.....you get a sequence of numbers that get smaller and smaller, (by a factor of ten) and clearly have a limit, as you take it to infinity.
That limit is zero, and so one is driven to conclude .9 recurring is one.
Just to throw a spanner in the works
x = 0.999...
10x = 9.999...
9x = 9.999... - x
but x = 0.999... so
9x = 9.999... - 0.999...
9x = 9
x = 1
This is supposed to prove that 0.999... = 1. It is in fact the way to convert recurring decimals to fractions. I think it falls over in the step 10x = 9.999... because you can't multiply an infinite series on one side of the equation and expect the same on the other. I.e.you're saying that infinity = infinity, or more to the point, infinity/infinity = 1 which, as far as I know is undefined (like n/0).
Thinking of it from that other perspective :
If you start at 1, and try to move away from 1 and toward 0.99999..., how far do you have to go to get to 0.99999... ? Any step you try to take will be too far, so you can't really move at all - which means that to move from 1 to 0.99999..., you have to stay at 1.