Crosswords1 min ago
How to work out the number of lamps in a set with given Voltage and Power.. Read Details
A set of decorative lights consist of a string of lamps. Each lamp is rated at 5.0V, 0.40W and is connected in series to a 230V supply.
I need to find out the number of lamps in the set, so that each lamp operates at the correct rating.
As well as this, I need to find out what the resistance of each lamp would be.
They are the details that I have been given. Please give me some idea AND a possible solution.
Thanks :)
I need to find out the number of lamps in the set, so that each lamp operates at the correct rating.
As well as this, I need to find out what the resistance of each lamp would be.
They are the details that I have been given. Please give me some idea AND a possible solution.
Thanks :)
Answers
From school I remember that:
- power in Watts= volts x amps
- resistance = voltage divided by current
I' m just guessing what you do next though. Maybe divide the 240 volts by the figure of 5 volts per bulb - that would give 48 bulbs
Then maybe total watts= 48 bulbs x 0.4= 19.6 watts
This may prompt further ideas
- power in Watts= volts x amps
- resistance = voltage divided by current
10:45 Sat 19th Sep 2009
From school I remember that:
- power in Watts= volts x amps
- resistance = voltage divided by current
I'm just guessing what you do next though. Maybe divide the 240 volts by the figure of 5 volts per bulb - that would give 48 bulbs
Then maybe total watts= 48 bulbs x 0.4= 19.6 watts
This may prompt further ideas
- power in Watts= volts x amps
- resistance = voltage divided by current
I'm just guessing what you do next though. Maybe divide the 240 volts by the figure of 5 volts per bulb - that would give 48 bulbs
Then maybe total watts= 48 bulbs x 0.4= 19.6 watts
This may prompt further ideas
The way I work out my consumption in my household is to calculate the power drawn from a socket in kW (amps) not the voltage. An electric Kettle can draw 3kW. Therefore the 3kW kettle would be the equivalent of 3000/.4 or 30,000/4 = 7,500 bulbs in current drawn. As factor30 says if you want to do an academic exercise you can use Ohm's Law.
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