Tricky question - can anyone help ...

[chokkie]

I am not sure which topic to put this under,but thought I'd go for "chatterbank" .....

Does any ABer out there know the answer to this question,please?

How many people need to be in a room to have more than a 50% chance of two of them having the same birthday?

Hope someone can help, many thanks, Chox

[Bbbananas]

Oh god, maths.
Quick exit >>>>>>>>>

[chokkie]

Did you know that, docspock, or have you just worked it out? Fascinated to know.

[joggerjayne]

Is this the Birthday Paradox ?

[Bbbananas]

I'd say 133.

[sara3]

if it helps, I'm Dec 11th x

[joggerjayne]

Would you settle for 23, Doc ?

[daffy654]

23

http://en.wikipedia.org/wiki/Birthday_problem

[Bbbananas]

Like I said - crap at maths.
No wonder I went bankrupt...... ;-)

[chokkie]

Many thanks guys, will go for 23. Thanks for your unbelievably prompt responses. Chox.

[joggerjayne]

Doc ... you and 22 others is correct.

But here's the crunch ...

With 23 people at a party, there's a 50% chance.

If there are two parties, in two adjacent houses, with 23 people at both parties ...

... now what are the chances ... ??

[Jemisa]

Gawd! My head hurts just thinking about it.
I went to a family gathering Sunday and there were 11 of us there and two had same birthday.

[chokkie]

someone where I work has got the same birthday as me (although she is younger) and she got married on the same day as OH and I did. Bizarre ....

[Jemisa]

The two at our gathering were the same age with the same birthday ---TWINS ha ha ha!

jem