Quizzes & Puzzles1 min ago
Why dissolve potassium sulphate in hydrochloric acid before adding barium chloride in a gravimetric analysis?
12 Answers
In labs today we analyzed sulphate ion content in a sample of K2SO4 by first dissolving in HCl and then reacting the solution with Barium chloride. Potassium sulphate dissolves in water, and the reaction for the displacement is K2SO4 + BaCl2----> BaSO4 + KCl. So why use HCl in the first place? Is there an intermediary step in the reaction I'm missing, or is it simply to dissolve the potassium sulphate? I have to write this up, and as it's not part of the reaction (as far as I know) I can't work it out. Assistance appreciated!
Answers
Yes, think that's it - either dissolve it in the acid first or acidify after mixing the two solutions . Otherwise, you won't get a good colloidal precipitate that will filter off properly!
11:50 Mon 01st Nov 2010
OK time for a definitive answer from a specialist. I hope you'll accept it as I'm a mere university Science Dean at a Russell Group university right now and hold Biochemistry Chairs in the UK and USA. It's quite a few years now since I was a Chemistry Reader at a university down the road but I'll give it my best shot. Hope it's good enough!
The K2SO4 solution is acidified with HCL for two reasons:
The first is that BaSO4 tends to crystallise in very tiny particles that have a tendency to occlude the formation of impurities. The acidification of the solution allows larger crystals of BaSO4 to form unhindered.
The second reason is that you have to remember that barium ions will precipitate other anions such as carbonates present in the K2SO4 as impurities. Acidifying the solution will largely prevent the precipitation of any carbonates, sulphites (as Teddio mentions) etc present.
The K2SO4 solution is acidified with HCL for two reasons:
The first is that BaSO4 tends to crystallise in very tiny particles that have a tendency to occlude the formation of impurities. The acidification of the solution allows larger crystals of BaSO4 to form unhindered.
The second reason is that you have to remember that barium ions will precipitate other anions such as carbonates present in the K2SO4 as impurities. Acidifying the solution will largely prevent the precipitation of any carbonates, sulphites (as Teddio mentions) etc present.
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