equation

[cpmcmahon]

Solve dy/dx = (y^2) + x

[rja211077]

i assume you need it solving for x. my a level maths is exceedingly rusty but i think it's xy^2 + x^2/2 + c ???

[cpmcmahon]

Thanks for your help, rja, but differentiating your answer would give dy/dx = (y^2) + 2xy(dy/dx) + x

[rja211077]

sorry my answer solved for y not x. y = xy^2 + 0.5x^2 + c. i'm 99.9% sure that dy/dx is therefore y^2 + x . For a basic guide to calculus go here http://www.tlchm.bris.ac.uk/~paulmay/misc/1s/calcl
t3.htm or type basic calculus into any search engine

[cpmcmahon]

Trouble is, you need to differentiate y wherever it appears. So in your answer, you need to differentiate y on the left side of the equation (which you did), and also on the right side of the equation where it appears as y^2 (which you didn't).

[tracymort]

omg! i've realised how much i have forgotton!