Quizzes & Puzzles0 min ago
Help with indices
13 Answers
Can someone please help with this question.
(2.5x10^2) x (4.5x10^-3) = 1.125x10^0
I thought if you multiplied numbers with indices you timesed the numbers then added the indices but 2+ -3 doesnt equal 0?
(2.5x10^2) x (4.5x10^-3) = 1.125x10^0
I thought if you multiplied numbers with indices you timesed the numbers then added the indices but 2+ -3 doesnt equal 0?
Answers
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No best answer has yet been selected by neddyw. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.you are right neddy, you do add the indices. As I tried to explain at the end of my post the answer comes out to 11.25 x 10^ -1 which you get from adding the indices.
They've gone one step further though and instead of 11.25 as the numerical bit they have divided by 10 to give 1.125. To keep the equality then the power has to be multiplied by 10:-
10^-1 x 10^1 = 10^0 = 1
It's just a different way of expressing the answer but is the same value
They've gone one step further though and instead of 11.25 as the numerical bit they have divided by 10 to give 1.125. To keep the equality then the power has to be multiplied by 10:-
10^-1 x 10^1 = 10^0 = 1
It's just a different way of expressing the answer but is the same value
Just to add to what's been written above:
A number is only said to be expressed in 'standard index form' (a x 10^b) when a is between 1 and 10. (a can be exactly equal to 1, but not to 10).
So, if you simply write the answer to your multiplication as 11.25 x 10^-1 you have failed to produce an answer in standard index form.
So it's necessary to write 11.25 in standard index form itself, and then to multiply it by 10^-1:
11.25 x 10^-1 = 1.125 x 10^1 x 10^-1 = 1.125 x 10^0
Simply keep it in mind that the first term must be between 1 and 10, then you won't go wrong ;-)
Chris
A number is only said to be expressed in 'standard index form' (a x 10^b) when a is between 1 and 10. (a can be exactly equal to 1, but not to 10).
So, if you simply write the answer to your multiplication as 11.25 x 10^-1 you have failed to produce an answer in standard index form.
So it's necessary to write 11.25 in standard index form itself, and then to multiply it by 10^-1:
11.25 x 10^-1 = 1.125 x 10^1 x 10^-1 = 1.125 x 10^0
Simply keep it in mind that the first term must be between 1 and 10, then you won't go wrong ;-)
Chris