News0 min ago
riddles
23 Answers
hi all,
does anyone know any good riddles, or
lateral thinkers, i have some family coming
over from canada, they love anything like that, anything very much appreciated,
a.l
does anyone know any good riddles, or
lateral thinkers, i have some family coming
over from canada, they love anything like that, anything very much appreciated,
a.l
Answers
Best Answer
No best answer has yet been selected by arnold lane. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.this really is a challenge....I've posted the link but this site wont allow the language so you have to substitute the letters marked with a * with a "a" and a "r"
http://b*sta*ds.alexconnect.net/1part/stage0.h tm
Good Luck :o)
http://b*sta*ds.alexconnect.net/1part/stage0.h tm
Good Luck :o)
Here's another - You have one glass of water and one glass of wine. Take a spoonful of water and add it to the wine, then stir. Next, take a spoonful of the wine (which is now diluted) and add this to the water (still pure). The question is this: Is there now more water in the wine, or wine in the water ?
Again, I will share the answer later - let's see what the other members think . . . .
Again, I will share the answer later - let's see what the other members think . . . .
John Alex, how do you get the dinky 1/2 sign to come up? I have done it the past but have completely forgotten. That's puzzling me more than the salmon.........is it anything to do with the weight the fisherman used?
Also whe wine one......... the original spoon of water doesn't have to have come from the glass so there would be more wine in the water.......
Also whe wine one......... the original spoon of water doesn't have to have come from the glass so there would be more wine in the water.......
Hi Sarumite
1. You'd be richer with �ton of �20 notes. Remember, you're not comparing the weight of a �20 note against one �10 note, but two! Best way to understand this problem is to cut a �20 note in half and place it alongside a �10 note, then weigh one against the other. The �10 note is heavier, so you'll get better value from the other side of the scales as you'll have to put more notes on, i.e. the Twenties!
2. Yes you're right - Salmon weighs 20lb. Most people say 15lb, then realise it doesn't work out! Quite simply, if it weighs 10lb plus half its weight then the first 10lb must be the other 'Half'. Therefore 10 + 10 = 20
Try these two teasers on your kids - good fun !
Thanks for your reply to the wine question - what do the rest of you think? Will clock on again tomorrow . . .
1. You'd be richer with �ton of �20 notes. Remember, you're not comparing the weight of a �20 note against one �10 note, but two! Best way to understand this problem is to cut a �20 note in half and place it alongside a �10 note, then weigh one against the other. The �10 note is heavier, so you'll get better value from the other side of the scales as you'll have to put more notes on, i.e. the Twenties!
2. Yes you're right - Salmon weighs 20lb. Most people say 15lb, then realise it doesn't work out! Quite simply, if it weighs 10lb plus half its weight then the first 10lb must be the other 'Half'. Therefore 10 + 10 = 20
Try these two teasers on your kids - good fun !
Thanks for your reply to the wine question - what do the rest of you think? Will clock on again tomorrow . . .
Hi Folks - Back to the wine question. If you take two identical glasses, with identical quantities of wine and water, then you can transfer as much as you like between the two, backwards and forwards, all day if you want to. As long as the levels of both glasses remain identical then so will the ratio of their contents, i.e. they will always be mirror images of each other. (Mohill - it doesn't make any difference whether you stir the contents or not!)
e.g. Glass A 90% + 10%, Glass B 10% + 90%
or... Glass A 37% + 63%, Glass B 63% + 37%, etc
There is no exception to this rule - if it's not in Glass A then it must be in Glass B (so Sarumite was correct!)
This principle works equally well with 2 buckets of different coloured sand (but don't mix the sand with the wine or you will get in a dreadful mess. . .)
Cheers! ja
e.g. Glass A 90% + 10%, Glass B 10% + 90%
or... Glass A 37% + 63%, Glass B 63% + 37%, etc
There is no exception to this rule - if it's not in Glass A then it must be in Glass B (so Sarumite was correct!)
This principle works equally well with 2 buckets of different coloured sand (but don't mix the sand with the wine or you will get in a dreadful mess. . .)
Cheers! ja