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How To Find The Two Numbers If The Hcf And Lcm Are Given?
18 Answers
For example, the LCM is 7700 and the HCF is 11?
Please tell me HOW? And how to do it for other numbers....
Please tell me HOW? And how to do it for other numbers....
Answers
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For more on marking an answer as the "Best Answer", please visit our FAQ.1) write the LCM in terms of its prime factors:- 7700 = 2² x 5² x 7 x 11
2) split those prime factors between a pair of numbers making sure that both have the HCF (also written in terms as its prime factors) in common and at least one of the numbers has the same power as each of primes
e.g. 2² x 5 x 11 and 2 x 5² x 7 x 11
2) split those prime factors between a pair of numbers making sure that both have the HCF (also written in terms as its prime factors) in common and at least one of the numbers has the same power as each of primes
e.g. 2² x 5 x 11 and 2 x 5² x 7 x 11
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I enjoyed that video.
Unless the numbers are small, always do a factor tree and then a Venn Diagram. As a short cut to find the LCM, if you can find the HCF you can calculate the LCM using the formula bibblebub gave.
The problem in your question (finding two numbers once you know their HCF and LCM) is an unusual one- I don't remember ever seeing that come up in an exam, so I wouldn't worry too much if you can't do this one.
Unless the numbers are small, always do a factor tree and then a Venn Diagram. As a short cut to find the LCM, if you can find the HCF you can calculate the LCM using the formula bibblebub gave.
The problem in your question (finding two numbers once you know their HCF and LCM) is an unusual one- I don't remember ever seeing that come up in an exam, so I wouldn't worry too much if you can't do this one.
The example you've given has several different solutions for the two numbers.
Starting from the HCF being 11, let's say one number is 11 * A, and the other is 11 * B, where A and B have NO common factor (because if they did, the HCF would be more than 11, okay?)
So their LCM is 11 * A * B which is given as 7700, therefore A * B = 700.
Now factoring 700 into "co-prime" factors gives us 4 * 7 * 25. You can see that if you split up the 4 between A and B, or the 25, you'd break the condition that A and B are to have no common factor. So the possible answers for A and B are (1) 25 and 28, (2) 7 and 100, (3) 4 and 225, or (4) 1 and 700.
Multiplying by 11, the possible answers to the original question "What two numbers have an HCF of 11 and an LCM of 7700?" are (1) 275 and 308, (2) 77 and 1100, (3) 44 and 2475, or (4) 11 and 7700. The more factors there are in the LCM, the more possible pairs of numbers there would be with the given HCF and LCM.
Starting from the HCF being 11, let's say one number is 11 * A, and the other is 11 * B, where A and B have NO common factor (because if they did, the HCF would be more than 11, okay?)
So their LCM is 11 * A * B which is given as 7700, therefore A * B = 700.
Now factoring 700 into "co-prime" factors gives us 4 * 7 * 25. You can see that if you split up the 4 between A and B, or the 25, you'd break the condition that A and B are to have no common factor. So the possible answers for A and B are (1) 25 and 28, (2) 7 and 100, (3) 4 and 225, or (4) 1 and 700.
Multiplying by 11, the possible answers to the original question "What two numbers have an HCF of 11 and an LCM of 7700?" are (1) 275 and 308, (2) 77 and 1100, (3) 44 and 2475, or (4) 11 and 7700. The more factors there are in the LCM, the more possible pairs of numbers there would be with the given HCF and LCM.
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