News1 min ago
Confused About This Problem
5 Answers
What is the minimum value of x for this inequality?
4x + 3( x - 1/5) ≥ 1/5( 2 + x )
4x + 3( x - 1/5) ≥ 1/5( 2 + x )
Answers
Best Answer
No best answer has yet been selected by ImagineDragons. Once a best answer has been selected, it will be shown here.
For more on marking an answer as the "Best Answer", please visit our FAQ.Typing equations (and inequalities) in a way which is clear to others online can be an absolute nightmare.
When it's written out by hand, does the fraction line in the first bracket pass under the whole of 'x -1'? (Or does the bracket simply contain 'x - one fifth'?)
Also, does the right-hand-side have a numerator of '1' and a denominator of '5(2 + x)'? (Or is the right-hand simply one fifth of '2 + x'?)
When it's written out by hand, does the fraction line in the first bracket pass under the whole of 'x -1'? (Or does the bracket simply contain 'x - one fifth'?)
Also, does the right-hand-side have a numerator of '1' and a denominator of '5(2 + x)'? (Or is the right-hand simply one fifth of '2 + x'?)
I agree with Buenchico of course.
Whatever the exact terms are, you need to multiply each bracket by the term outside and then collect like terms.
So, assuming yours is exactly as written you would have
4x +3x - 3/5 ≥ 2/5 +x/5
then collect like terms:
7x - 3/5 ≥ x/5 +2/5
then rearrange, by doing the same to both sides of the equality
34x/5 ≥ 1
so 34x ≥5
I'll let you do the last step.
If it's written incorrectly and the terms are algebraic fractions so you have terms involving x as denominators then it's trickier to rearrange
Whatever the exact terms are, you need to multiply each bracket by the term outside and then collect like terms.
So, assuming yours is exactly as written you would have
4x +3x - 3/5 ≥ 2/5 +x/5
then collect like terms:
7x - 3/5 ≥ x/5 +2/5
then rearrange, by doing the same to both sides of the equality
34x/5 ≥ 1
so 34x ≥5
I'll let you do the last step.
If it's written incorrectly and the terms are algebraic fractions so you have terms involving x as denominators then it's trickier to rearrange