Must go with Fibonacci on this one; mjd says the hands must cross on the hour, but they actually co-incide in the sixty minutes following each hour. The meeting after eleven o'clock takes place on the stroke of twelve, and the hands co-incide rather than cross.
The question doesn't say you start at midnight, so to avoid coincide-versus-cross confusion, start at a time when hands are separate, say 3.30 which is the time as I type. Then the hands will cross eleven times, at (approx) 4.22, 5.27, 6.33, 7.33, 8.44, 9.49, 10.55, 12.00, 1.05, 2.11 and 3.16.
As the clock ticks round ... HANDS only CROSS ONCE in every hour
So, in a 12 hour period .... The hands will cross ELEVEN times ... since the hands do NOT cross -
EITHER - at the start (if you start with the hands together)
OR - (if you do not start with the hands together) at the end (where the hands draw up to the starting time but do NOT cross, since the 12 hours is up!