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emailia | 18:48 Sun 05th Mar 2006 | Science
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Hello


I really need to know the equation for the burning of ethanol, propanol, butanol etc., and also the molecule structure- can anyone help?! Thanks!

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Ethanol

C<sub>2</sub>H<sub>5</sub>OH+3O<sub>2</sub>= 2CO<sub>2</sub>+3H<sub>2</sub>0
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Ethanol - 1 molecule of ethanol, plus 3 molecules of Oxygen = 2 molecules of Carbon Dioxide, plus 3 molecules of water

C2H5OH +3 O2 = 2 CO2 + 3 H2O

Combustion of propanol: 2 Propanol + 9 Oxygen > 6 Carbon dioxide + 8 Water


Combustion of butanol: Butanol + 6 Oxygen > 4 Carbon dioxide + 5 Water


Propanol is C3H7OH and butanol is C4H9OH; in equations above oxygen is O2, don't forget. The combustion of these simple aliphatic alcohols always yield carbon dioxide and water in sufficient oxygen levels but carbon monoxide in lower levels.


The structure of these alcohols is formed by drawing the "C"s in a line, adding an -OH group on the end, add -H atoms to the rest of the carbons so that they all share four bonds with other atoms in the molecule.


I hope this is helpful.

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thank you : ) v helpful

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