With all due respect blue orchid, I have to point out that you have over-simplified the chemical reaction that occurs here.
What happens is that the cupric ion that is complexed with the citrate ion in the Benedict's Solution is reduced to a cuprous ion by the oxidised functional aldehyde group (-CHO) in the reducing sugar.
This does indeed precipitate out but you should note that the test is semi-quantitative as well as qualitatitive. This is because the precipitate goes through colour changes from blue, to green, to yellow, to orange, to red and finally to brick-red depending on the concentration of the reducing sugar in the sample under analysis. Because of this the final precipitate may not necessarily be red-brown in colour - it can be any of the other colours in the sequence under certain circumstances.
This variation is sometimes known as the Benedict's Quantitative Test although you should note that the same reagant is used.
Concentrations of reducing sugars from around 0.05% to 3% can be roughly measured in this way and for many years, this was the only means of testing the percentage concentration of reducing sugars in urine.
Finally, the reduced cuprous ion precipitates out as cuprous (1) oxide, not "copper sulphide".